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Let's solve the problem step by step using the given dataLet's solve the problem step by step using the given  6, 12, 5, 7, 7, 3, 9.

We need to calculate the **mean**, **median**, **range**, and **midrange**.

1. **Mean**: 
   The mean is the average of the numbers. 
   \[
   \text{Mean} = \frac{6 + 12 + 5 + 7 + 7 + 3 + 9}{7} = \frac{49}{7} = 7
   \]

2. **Median**:
   The median is the middle number when the data is arranged in order.
   The ordered data is: 3, 5, 6, 7, 7, 9, 12. 
   The middle value is 7.

3. **Range**:
   The range is the difference between the largest and smallest numbers.
   \[
   \text{Range} = 12 - 3 = 9
   \]

4. **Midrange**:
   The midrange is the average of the largest and smallest numbers.
   \[
   \text{Midrange} = \frac{12 + 3}{2} = \frac{15}{2} = 7.5
   \]

### Final answers:
- Mean = 7
- Median = 7
- Range = 9
- Midrange = 7.5

Therefore, the correct option is the first one:
- **Mean, 7; Median, 7; Range, 9; Midrange, 7.5**

Would you like more details or have any questions?

Here are 5 related questions for further understanding:
1. How does the mean change if one number in the data set increases by 3?
2. What would be the median if there were 8 numbers instead of 7?
3. How is the range affected by outliers in a data set?
4. Can the median ever be larger than the range?
5. What is the significance of midrange in real-world applications?

**Tip**: When calculating the mean, make sure all numbers are included to avoid errors.

Calculate the mean, median, range, and midrange of the number of cups of tea sold for the week. The data is: 6, 12, 5, 7, 7, 3, 9.

Learn how to calculate the mean, median, range, and midrange for a set of data representing cups of tea sold over a week. Understand key mathematical concepts with a detailed step-by-step solution. Suitable for students in Grades 5-7.

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