Two ropes of length 16 m and 24 m are to be cut into small pieces of equal lengths. What will be the maximum length of each piece. Write this with statement

The maximum length of each piece will be the greatest common divisor (GCD) of the lengths of the two ropes, which are 16 meters and 24 meters.

To find the GCD:
- The factors of 16 are: 1, 2, 4, 8, 16
- The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The greatest common factor is 8.

**Therefore, the maximum length of each piece that can be cut from both ropes is 8 meters.**

Would you like more details or have any questions? 

Here are 5 related questions:
1. How many pieces of 8 meters can be cut from each rope?
2. What if the ropes were 18 meters and 27 meters long—what would the maximum length of each piece be?
3. How would the solution change if the lengths were in centimeters instead of meters?
4. What is the least common multiple (LCM) of 16 and 24?
5. How is the GCD useful in other practical situations?

**Tip:** The GCD is a useful tool for solving problems involving divisibility and is often applied in simplifying fractions and dividing quantities evenly.

Discover how to calculate the maximum length of each piece from two ropes, 16 meters and 24 meters long. Learn the concept of Greatest Common Divisor (GCD) and its application in determining equal piece lengths. Suitable for Grades 7-9 students.

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