We are given the problem of determining the total mass of a glass container filled with water. Let's break this down step by step.

Given:

• Density of water: $1,000 \, \text{kg/m}^3$
• Mass of the empty container: $2.5 \, \text{kg}$
• Dimensions of the container:
  • Length: $10 \, \text{cm} = 0.10 \, \text{m}$
  • Width: $5 \, \text{cm} = 0.05 \, \text{m}$
  • Height: $25 \, \text{cm} = 0.25 \, \text{m}$

Steps:

1. Find the volume of the container: The volume of a rectangular container is given by: $V = \text{length} \times \text{width} \times \text{height}$ Substituting the dimensions of the container: $V = 0.10 \, \text{m} \times 0.05 \, \text{m} \times 0.25 \, \text{m}$ Let me calculate this for you.

   $V = 0.00125 \, \text{m}^3$

2. Find the mass of the water: The mass of water is found using the formula: $\text{mass of water} = \text{density of water} \times \text{volume}$ Substituting the values: $\text{mass of water} = 1,000 \, \text{kg/m}^3 \times 0.00125 \, \text{m}^3$ $\text{mass of water} = 1.25 \, \text{kg}$

3. Find the total mass: The total mass is the sum of the mass of the container and the mass of the water: $\text{total mass} = \text{mass of container} + \text{mass of water}$ $\text{total mass} = 2.5 \, \text{kg} + 1.25 \, \text{kg}$ $\text{total mass} = 3.75 \, \text{kg}$

Final Answer:

The total mass of the container when filled with water is 3.75 kg.

If you'd like more details or further clarification, feel free to ask! Here are some related questions to think about:

1. How would the total mass change if the container had a different height?
2. What would happen if the container had irregular dimensions?
3. How would the total mass change if the container were filled with a liquid denser than water?
4. What if the container had a different mass but the same dimensions—how would the result change?
5. How could you convert the mass of water to volume if you knew the mass but not the dimensions of the container?

Tip: Always ensure units are consistent when performing calculations.