Math Problem Statement
Solution
Let's go through the given problem step by step:
-
Pool Dimensions:
- Length = 38.1 m
- Width = 38.8 m
- Depth = 8.20 ft
-
Density of Water:
The density of water is given as , which is equivalent to . -
Unit Conversion:
- We need to convert the depth from feet to meters since the other dimensions are in meters. The conversion factor is given: Therefore,
-
Volume of Water: The volume of the pool can be found using the formula for the volume of a rectangular prism: Substituting the values:
-
Mass of Water: The mass of water is found using the formula: Using the density of water , the mass can be calculated after finding the volume.
I'll calculate the values.The mass of the water in the pool is approximately .
Would you like more details or have any questions about this calculation?
Here are 5 related questions to expand on this topic:
- How would the mass change if the depth of the pool increased by 1 foot?
- What is the mass of water in pounds (lb)?
- How do significant figures affect the final result in this calculation?
- How would the result change if the pool was filled with a liquid denser than water?
- What are the implications of water density changes with temperature?
Tip: Always ensure consistent units in calculations to avoid errors in physical computations.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Unit Conversion
Volume Calculation
Mass Calculation
Formulas
Volume = Length × Width × Depth
Mass = Density × Volume
Theorems
Dimensional Analysis
Suitable Grade Level
Grades 10-12