Math Problem Statement

Circle Ω has diameter AB = 5. Circles ω1 and ω2 have radii 1 and 2 respectively, and are internally tangent to Ω at A and B respectively. The common chord of ω1 and ω2 intersects Ω at P and Q. What is the length of PQ?

Solution

To solve this problem, we need to analyze the relationship between the given circles and the chord PQPQ that intersects the circle Ω\Omega.

Step 1: Understanding the Geometry

  • Ω\Omega is the large circle with a diameter AB=5AB = 5.
  • ω1\omega_1 and ω2\omega_2 are smaller circles internally tangent to Ω\Omega at points AA and BB respectively.
    • ω1\omega_1 has a radius r1=1r_1 = 1.
    • ω2\omega_2 has a radius r2=2r_2 = 2.
  • PP and QQ are the points where the common chord of ω1\omega_1 and ω2\omega_2 intersects Ω\Omega.

Step 2: Using Power of a Point Theorem

The key to solving this problem is applying the power of a point theorem. The power of a point PP with respect to a circle is given by PAPB|PA \cdot PB| for any point PP outside the circle.

Step 3: Coordinate System Setup

Let's set up a coordinate system:

  • Place AA at (52,0)(-\frac{5}{2}, 0) and BB at (52,0)(\frac{5}{2}, 0).
  • The center OO of Ω\Omega is at the origin (0,0)(0, 0).

For the smaller circles:

  • The center of ω1\omega_1 is at A1A_1 located at (32,0)(-\frac{3}{2}, 0) with a radius of 1.
  • The center of ω2\omega_2 is at A2A_2 located at (12,0)(\frac{1}{2}, 0) with a radius of 2.

Step 4: Distance Between Centers of ω1\omega_1 and ω2\omega_2

The distance dd between the centers A1A_1 and A2A_2 is: d=A1A2=12(32)=2d = |A_1 A_2| = \left|\frac{1}{2} - \left(-\frac{3}{2}\right)\right| = 2

Step 5: Length of Common Chord PQ

To find the length of the common chord PQPQ, we use the fact that the length of the common chord between two intersecting circles is given by: PQ=2r12(d2+r12r222d)2PQ = 2 \sqrt{r_1^2 - \left(\frac{d^2 + r_1^2 - r_2^2}{2d}\right)^2} Substituting the values: PQ=212(22+122222)2PQ = 2 \sqrt{1^2 - \left(\frac{2^2 + 1^2 - 2^2}{2 \cdot 2}\right)^2} Simplifying further: PQ=21(4+144)2=21(14)2=21116=21516=2154=152PQ = 2 \sqrt{1 - \left(\frac{4 + 1 - 4}{4}\right)^2} = 2 \sqrt{1 - \left(\frac{1}{4}\right)^2} = 2 \sqrt{1 - \frac{1}{16}} = 2 \sqrt{\frac{15}{16}} = \frac{2 \cdot \sqrt{15}}{4} = \frac{\sqrt{15}}{2}

Final Answer

The length of PQPQ is 15\sqrt{15}.

Let me know if you want more details or have any questions. Here are some related questions you might be interested in:

  1. How does the power of a point theorem apply to this situation?
  2. What are the properties of the common chord of two intersecting circles?
  3. How can the equation of a circle be used to find the length of a chord?
  4. What happens to the common chord's length if the radii of the circles change?
  5. How does the internal tangency of circles affect the geometry of the system?

Tip: When dealing with circle problems, always consider the power of a point theorem as it is a powerful tool for finding distances and lengths related to chords and tangents.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Geometry
Power of a Point Theorem

Formulas

Length of common chord between intersecting circles

Theorems

Power of a Point Theorem

Suitable Grade Level

Advanced High School