https://file.aiquickdraw.com/mathbot/file/1730137170443uzse6vc0.jpg

This is a right-angled triangle, and we can use Pythagoras' theorem to find the length of \( PR \). 

Pythagoras' theorem states:
\[
PR^2 + RQ^2 = PQ^2
\]

We know:
- \( PQ = 30 \, \text{cm} \)
- \( RQ = 24 \, \text{cm} \)

Now, substitute the values into the equation:

\[
PR^2 + 24^2 = 30^2
\]
\[
PR^2 + 576 = 900
\]
\[
PR^2 = 900 - 576 = 324
\]
\[
PR = \sqrt{324} = 18 \, \text{cm}
\]

Therefore, the length of \( PR \) is **18 cm**.

Would you like any further details or have any questions? Here are some related questions you might find useful:

1. What is the general formula for Pythagoras' theorem?
2. How can Pythagoras' theorem be applied in 3D space?
3. Can Pythagoras' theorem be used for non-right-angled triangles?
4. How do you calculate the length of a diagonal in a rectangle using Pythagoras' theorem?
5. What are some real-world applications of Pythagoras' theorem?

**Tip:** When applying Pythagoras' theorem, make sure the triangle is a right triangle before using the formula.

Using Pythagoras' theorem, calculate the length of PR. Give your answer in centimetres (cm) and give any decimal answers to 1 d.p.

Solve for the length of PR in a right-angled triangle using Pythagoras' theorem. This example covers key geometry concepts and demonstrates step-by-step calculations, ideal for students in Grades 6-8.

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