To find the **x-component** of vector **a** with a magnitude of 35 N at an angle of 55° North of East, we use trigonometry. Since the x-component refers to the projection of the vector along the eastward (horizontal) axis, we apply the **cosine** function because it relates to the adjacent side of the angle.

Given:
- Magnitude \( a = 35 \, \text{N} \)
- Angle \( \theta = 55^\circ \)

The x-component is calculated as:

\[
a_x = a \cdot \cos(\theta)
\]

\[
a_x = 35 \cdot \cos(55^\circ)
\]

Now let's calculate this value:

\[
a_x \approx 35 \cdot 0.5736 = 20.08 \, \text{N}
\]

Thus, the **x-component** of the vector is approximately **20.08 N**.

Would you like to go over any specific details or clarify further?

Here are 5 related questions:
1. How would you find the y-component of the same vector?
2. What is the total resultant vector when combining multiple vectors?
3. How does changing the angle affect the x and y components?
4. What is the significance of vector components in physics problems?
5. How do you find the angle of a vector if its components are given?

**Tip:** Always use the correct trigonometric function based on the axis and angle orientation when dealing with vector components.

x component of a = 35 N at 55° North of East

Discover how to calculate the x-component of a vector with a magnitude of 35 N at an angle of 55° North of East. This step-by-step guide explains the use of trigonometric functions and formulas to resolve vectors into components, ideal for high school physics and math students.

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