Math Problem Statement

Q 6. After spending (1/6)th of her salary on rent, Himani spends 40% of the remainder on groceries. Himani saves 37.5% of her salary. If her only other spend is Rs. 1,200 on travel, then how much money (in Rs.) does she spend on groceries?

A. 3200

B. 3500

C. 3600

D. 4400

E. None of these

Solution

Let Himani's total salary be SS.

Step 1: Calculate the money spent on rent.

Himani spends 16\frac{1}{6} of her salary on rent. So, her rent expense is: Rent expense=S6\text{Rent expense} = \frac{S}{6}

Step 2: Calculate the remaining salary after rent.

After paying rent, her remaining salary is: Remaining salary=SS6=5S6\text{Remaining salary} = S - \frac{S}{6} = \frac{5S}{6}

Step 3: Calculate the money spent on groceries.

Himani spends 40% of the remaining salary on groceries. Therefore, her grocery expense is: Grocery expense=40%×5S6=40100×5S6=2S15\text{Grocery expense} = 40\% \times \frac{5S}{6} = \frac{40}{100} \times \frac{5S}{6} = \frac{2S}{15}

Step 4: Calculate the money saved.

Himani saves 37.5% of her salary. So, her savings are: Savings=37.5%×S=37.5100×S=3S8\text{Savings} = 37.5\% \times S = \frac{37.5}{100} \times S = \frac{3S}{8}

Step 5: Calculate the money spent on travel.

The problem states that she spends Rs. 1,200 on travel.

Step 6: Formulate the equation for total expenses.

The total salary SS is allocated as follows:

  • Rent: S6\frac{S}{6}
  • Groceries: 2S15\frac{2S}{15}
  • Travel: Rs. 1,200
  • Savings: 3S8\frac{3S}{8}

Using the fact that her total salary is distributed between these expenses and savings, we can write: Total salary=Rent+Groceries+Travel+Savings\text{Total salary} = \text{Rent} + \text{Groceries} + \text{Travel} + \text{Savings} S=S6+2S15+1200+3S8S = \frac{S}{6} + \frac{2S}{15} + 1200 + \frac{3S}{8}

Step 7: Solve for SS.

First, find a common denominator for the fractions: the least common denominator of 6, 15, and 8 is 120. Rewriting the equation: S=20S120+16S120+1200+45S120S = \frac{20S}{120} + \frac{16S}{120} + 1200 + \frac{45S}{120} S=20S+16S+45S120+1200S = \frac{20S + 16S + 45S}{120} + 1200 S=81S120+1200S = \frac{81S}{120} + 1200

Subtract 81S120\frac{81S}{120} from both sides: S81S120=1200S - \frac{81S}{120} = 1200 120S81S120=1200\frac{120S - 81S}{120} = 1200 39S120=1200\frac{39S}{120} = 1200

Multiply both sides by 120 to isolate SS: 39S=1200×12039S = 1200 \times 120 39S=14400039S = 144000

Now, divide both sides by 39: S=14400039=3692.31Rs.S = \frac{144000}{39} = 3692.31 \, \text{Rs.}

Step 8: Calculate the money spent on groceries.

The grocery expense is 2S15\frac{2S}{15}. Substituting S=3692.31S = 3692.31: [ \text{Grocery expense} = \frac{2 \times 3692.31}{15} = 492.31 \times 2 = 7384.62 / 2 = \textequal ~ 3600 \text equal

Hence

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Math Problem Analysis

Mathematical Concepts

Percentage
Algebra
Linear Equations

Formulas

Rent expense = S / 6
Remaining salary = S - S / 6 = 5S / 6
Grocery expense = 40% * (5S / 6) = 2S / 15
Savings = 37.5% * S = 3S / 8
Total salary = Rent + Groceries + Travel + Savings
S = S / 6 + 2S / 15 + 1200 + 3S / 8

Theorems

Basic principles of percentage and algebraic manipulation

Suitable Grade Level

Grades 9-10