Math Problem Statement
Solution
To solve this problem, let's analyze the information provided and calculate the magnitude of .
Given Data:
- Radius of disk () = 1.6 cm = 0.016 m
- Mass of disk () = 20 grams = 0.02 kg
- Initial angular velocity () = 0 (since it starts from rest)
- Final angular velocity () = 280 rad/s (counterclockwise)
- Time interval () = 1.2 s
- Force = 0.096 N
The question requires us to find the magnitude of the force .
Approach:
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Calculate the moment of inertia (I) of the disk: For a uniform disk rotating around its center, the moment of inertia is:
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Calculate the angular acceleration (): Using the formula for angular acceleration:
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Calculate the net torque (): Torque () is related to angular acceleration by:
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Set up the equation for net torque with and : Since the forces are applied tangentially, the torque due to each force is: Since we know , we can solve for .
Let's go through the calculations:
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Moment of inertia:
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Angular acceleration:
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Net torque:
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Torque equation with and : Substituting , , and :
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Solve for :
Answer:
The magnitude of is approximately .
Would you like a further breakdown of any part of this solution?
Here are some related questions you might consider:
- How would the solution change if the disk had a different mass?
- What if the disk’s radius were larger? How would be affected?
- How does the direction of the forces impact the angular velocity?
- Can this approach be applied to non-uniform objects, like a ring?
- What role does the moment of inertia play in rotational dynamics?
Tip: Always double-check unit conversions, especially when switching from grams to kilograms or centimeters to meters.
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Math Problem Analysis
Mathematical Concepts
Rotational Motion
Angular Acceleration
Torque
Moment of Inertia
Formulas
Moment of Inertia for a disk I = (1/2) * m * R^2
Angular acceleration α = (ω - ω0) / t
Torque τ = I * α
Net torque equation τ = F1 * R - F2 * R
Theorems
Newton's Second Law for Rotation (τ = I * α)
Suitable Grade Level
Undergraduate Physics
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