To solve for the final velocity of the automobile, we can use the kinematic equation:

$v_f = v_i + a \cdot t$

where:

• $v_f$ is the final velocity,
• $v_i$ is the initial velocity,
• $a$ is the acceleration,
• $t$ is the time.

Given:

• Initial velocity, $v_i = 4 \, \text{m/s}$
• Acceleration, $a = 4 \, \text{m/s}^2$
• Time, $t = 2.55 \, \text{s}$

Now, plug in the values:

$v_f = 4 \, \text{m/s} + (4 \, \text{m/s}^2 \times 2.55 \, \text{s})$

Calculate the final velocity:

$v_f = 4 \, \text{m/s} + 10.2 \, \text{m/s} = 14.2 \, \text{m/s}$

So, the final velocity of the automobile is 14.2 m/s.

Would you like to see more details or have any other questions?

Here are 5 related questions to consider:

1. How far does the automobile travel during this acceleration period?
2. If the acceleration rate changes, how would that affect the final velocity?
3. What would be the final velocity if the automobile had started from rest?
4. How long would it take for the automobile to reach a velocity of 20 m/s with the same acceleration?
5. What happens to the velocity if the acceleration is negative?

Tip: Always ensure the units are consistent when solving physics problems to avoid calculation errors.