Let's solve this physics problem step by step.

We are given:

• Initial velocity ($u$) = 0 m/s (since the car starts at rest)
• Acceleration ($a$) = 2.34 m/s²
• Distance ($s$) = 0.64 km = 640 m (converted from kilometers to meters)

We need to find the final velocity ($v$) using the equation of motion: $v^2 = u^2 + 2as$ Since $u = 0$, the equation simplifies to: $v^2 = 2as$ $v = \sqrt{2as}$

Now we can substitute the given values: $v = \sqrt{2 \times 2.34 \, \text{m/s}^2 \times 640 \, \text{m}}$

Let me calculate the result for you.The calculated final velocity is approximately $54.7284$ m/s.

Since you are required to give the answer with only 2 decimal places and no rounding in the final result, the answer is $54.73$.

Would you like more details or have any questions?

Here are 5 related questions to deepen understanding:

1. How would the final velocity change if the acceleration was doubled?
2. What equation would you use if the car had an initial velocity?
3. How do you convert the final velocity into km/h?
4. What would happen to the final velocity if the distance traveled was halved?
5. How would air resistance affect this scenario?

Tip: Always convert all units to standard SI units before performing calculations.