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The given equation states that the number of seconds, \( n \), is inversely proportional to the power of the kettle, \( p \), in kilowatts. The relationship is provided as:

\[
n = \frac{280}{p}
\]

We are tasked with finding the power \( p \) if the kettle takes \( n = 70 \) seconds to boil.

To find \( p \), we rearrange the formula:

\[
p = \frac{280}{n}
\]

Substituting \( n = 70 \):

\[
p = \frac{280}{70} = 4 \, \text{kW}
\]

Thus, the power of the kettle is **4.0 kW**.

Would you like more details or have any further questions?

Here are 5 related questions:
1. What does it mean for two quantities to be inversely proportional?
2. How would the equation change if the time taken to boil doubled?
3. Can you derive the value of \( p \) if the time to boil was 35 seconds?
4. How does the proportionality constant \( 280 \) affect the power and time relationship?
5. What unit conversion would you perform if the power was in watts instead of kilowatts?

**Tip:** Always check units carefully when solving proportionality problems, as they can affect the outcome of the equation.

The number of seconds that it takes for a kettle to boil, n, is inversely proportional to its power in kilowatts, p. The equation of proportionality is n = 280/p. Work out the power of the kettle if it takes 70 seconds to boil. If your answer is a decimal, give it to 1 d.p.

Solve an inverse proportionality problem where the boiling time of a kettle is inversely proportional to its power. Learn how to calculate the kettle's power if it takes 70 seconds to boil, with the equation n = 280 / p. Suitable for students in Grades 8-10.

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