How much energy is required to raise the temperature of 325 g of water from 74°C to 293°C?  The specific heat of water is 4.18 J/g∙C

(round your answer to the nearest whole number)

How much energy is required to raise the temperature of 325 g of water from 74°C to 293°C?  The specific heat of water is 4.18 J/g∙C

(round your answer to the nearest whole number)



To calculate the energy required to raise the temperature of water, we use the formula:

\[
Q = mc\Delta T
\]

Where:
- \( Q \) is the energy required (in joules),
- \( m \) is the mass of the water (in grams),
- \( c \) is the specific heat capacity of water \((4.18 \, \text{J/g°C})\),
- \( \Delta T \) is the change in temperature (in °C).

Given:
- Mass, \( m = 325 \, \text{g} \),
- Specific heat, \( c = 4.18 \, \text{J/g°C} \),
- Initial temperature, \( T_1 = 74°C \),
- Final temperature, \( T_2 = 293°C \).

The change in temperature, \( \Delta T \), is:

\[
\Delta T = T_2 - T_1 = 293°C - 74°C = 219°C
\]

Now, substitute the values into the formula:

\[
Q = 325 \, \text{g} \times 4.18 \, \text{J/g°C} \times 219°C
\]

Let me calculate that for you.

The energy required to raise the temperature of 325 g of water from 74°C to 293°C is approximately **297,512 joules** (rounded to the nearest whole number).

Would you like further details on this calculation or have any questions?

Here are 5 related questions to expand on this:
1. How does the specific heat capacity of water compare to other substances?
2. How is the energy required affected if the mass of water changes?
3. What would happen if the specific heat capacity of the substance was lower?
4. How does phase change (e.g., boiling) impact the calculation of energy required?
5. What is the formula for calculating energy if the water undergoes a phase change?

**Tip:** The specific heat of a substance indicates how much energy is needed to change its temperature; water's high specific heat means it requires more energy compared to most substances.

How much energy is required to raise the temperature of 325 g of water from 74°C to 293°C? The specific heat of water is 4.18 J/g∙C (round your answer to the nearest whole number)

Find out how to calculate the energy required to heat 325 g of water from 74°C to 293°C. Using the heat energy formula Q = mcΔT and the specific heat of water (4.18 J/g°C), this problem covers essential thermodynamic concepts. Ideal for students in Grades 9-12.

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