300g of water is at 12.0c the water absorbs 4016j of heat energy. what is the new temperature of the water

To determine the new temperature of the water after it absorbs 4016 J of heat energy, we can use the following formula:

\[
q = mc\Delta T
\]

Where:
- \(q\) is the heat energy absorbed (in joules, J),
- \(m\) is the mass of the water (in grams, g),
- \(c\) is the specific heat capacity of water (\(4.18 \, \text{J/g°C}\)),
- \(\Delta T\) is the change in temperature (in °C).

### Step 1: Rearrange the formula to solve for \(\Delta T\):

\[
\Delta T = \frac{q}{mc}
\]

### Step 2: Plug in the known values:
- \(q = 4016 \, \text{J}\),
- \(m = 300 \, \text{g}\),
- \(c = 4.18 \, \text{J/g°C}\).

\[
\Delta T = \frac{4016}{300 \times 4.18}
\]

Let's calculate this:

\[
\Delta T = \frac{4016}{1254} \approx 3.2°C
\]

### Step 3: Calculate the new temperature:
The initial temperature is \(12.0°C\), so the new temperature is:

\[
T_{\text{new}} = 12.0°C + 3.2°C = 15.2°C
\]

### Conclusion:
The new temperature of the water is approximately **15.2°C**.

Would you like more details or have any questions?

Here are 5 related questions you might explore:
1. What happens to the temperature if a different amount of heat is absorbed?
2. How would the result change if the mass of water was different?
3. Can this formula be used for other substances? Why or why not?
4. What is the significance of the specific heat capacity of water?
5. How does heat energy affect phase changes in water?

**Tip:** Always ensure that the units of mass, specific heat, and temperature are compatible when using the heat energy formula.

300g of water is at 12.0°C. The water absorbs 4016 J of heat energy. What is the new temperature of the water?

Learn how to calculate the new temperature of 300g of water initially at 12.0°C after absorbing 4016 J of heat energy. This step-by-step guide covers thermodynamics principles and heat energy transfer, using the q = mcΔT formula. Suitable for high school students in Grades 9-12.

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