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To solve the problem using the formula \( d = rt \), where:

- \( d \) is the distance traveled,
- \( r \) is the rate (speed), and
- \( t \) is the time.

Here are the given values:
- \( r = 67 \) miles per hour
- \( t = 4.25 \) hours

We calculate the distance \( d \) by multiplying the rate and the time:

\[
d = 67 \times 4.25
\]

\[
d = 284.75 \text{ miles}
\]

The correct answer is \( \boxed{284.75 \text{ miles}} \).

Would you like more details or have any questions?

Here are 5 related questions:
1. How would the distance change if Jim traveled at 70 miles per hour for the same duration?
2. What would the time be if Jim traveled 300 miles at 67 miles per hour?
3. How do you convert the distance to kilometers if 1 mile is approximately 1.60934 kilometers?
4. If Jim took a 30-minute break during the trip, how would this affect the calculation?
5. How would you represent the formula \( d = rt \) in terms of time if the distance and rate are given?

**Tip:** Remember to keep track of units when solving problems involving distance, speed, and time to avoid errors.

If Jim traveled 67 miles per hour for 4.25 hours, calculate the distance he traveled.

Learn how to calculate the distance Jim traveled by applying the formula d = rt. Jim traveled 67 miles per hour for 4.25 hours, resulting in a total distance of 284.75 miles. This problem involves key algebraic concepts suitable for students in Grades 6-8.

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