A fox runs for 9.4 s at the speed of 10.6 m/s. What distance does he cover? Round to the nearest 0.1 m?

To find the distance covered by the fox, we can use the formula for distance when speed and time are known:

\[
\text{Distance} = \text{Speed} \times \text{Time}
\]

Given:
- Speed \( v = 10.6 \, \text{m/s} \)
- Time \( t = 9.4 \, \text{s} \)

Now, calculate the distance:

\[
\text{Distance} = 10.6 \times 9.4
\]

Let's compute that.The fox covers a distance of approximately **99.6 meters**.

Would you like to explore further details or have any questions? Here are some related questions:

1. What would be the distance covered if the fox ran for 15 seconds?
2. How long would it take the fox to cover 150 meters at the same speed?
3. If the speed increased by 20%, what distance would the fox cover in the same time?
4. How does the distance change if the fox slows down to 8 m/s after 5 seconds?
5. How much time would the fox need to double the distance at the same speed?

**Tip:** Always ensure the units for speed and time are consistent when calculating distance.

Learn how to calculate the distance covered by a fox running at 10.6 meters per second for 9.4 seconds. This problem involves basic kinematic principles, including the formula for distance calculation based on speed and time. Suitable for students in Grades 7-9.

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