The points \((-6, 8)\) and \((-13, 8)\) lie on a horizontal line because their \(y\)-coordinates are the same (both are 8).

To find the **distance** between these two points, we can apply the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Since the \(y\)-coordinates are the same, the difference between them will be 0. So, the formula simplifies to:

\[
d = |x_2 - x_1|
\]

Substituting the values:

\[
d = |-13 - (-6)| = |-13 + 6| = |-7| = 7
\]

Thus, the distance between the two points is **7 units**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you find the distance between two points with different \(y\)-coordinates?
2. What is the equation of the line that passes through \((-6, 8)\) and \((-13, 8)\)?
3. How would you find the midpoint of the segment between these two points?
4. How do you find the slope between two points with the same \(y\)-coordinate?
5. What would be the distance between two points that have the same \(x\)-coordinate?

**Tip:** For points with the same \(y\)-coordinate, the distance is simply the absolute difference between their \(x\)-coordinates.

Understand how to calculate the distance between the points (-6, 8) and (-13, 8) on a horizontal line using the distance formula. This problem explores coordinate geometry concepts and is suitable for students in Grades 6-8.

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