Math Problem Statement

what is the distance between (-6,8) and (-3,9)

Solution

To find the distance between two points (6,8)(-6, 8) and (3,9)(-3, 9) in a coordinate plane, you can use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Here, (x1,y1)=(6,8)(x_1, y_1) = (-6, 8) and (x2,y2)=(3,9)(x_2, y_2) = (-3, 9). Plugging in the values:

d=(3(6))2+(98)2d = \sqrt{(-3 - (-6))^2 + (9 - 8)^2}

Simplifying further:

d=(3+6)2+(98)2d = \sqrt{(-3 + 6)^2 + (9 - 8)^2} d=(3)2+(1)2d = \sqrt{(3)^2 + (1)^2} d=9+1d = \sqrt{9 + 1} d=10d = \sqrt{10}

So, the distance between the points is 10\sqrt{10}.

Would you like more details or have any questions about this solution?

Here are 5 related questions you might find interesting:

  1. How do you find the midpoint between two points in a coordinate plane?
  2. What is the slope of the line passing through points (6,8)(-6, 8) and (3,9)(-3, 9)?
  3. How do you find the equation of a line given two points?
  4. What is the distance between the origin and the point (4,5)(4, 5)?
  5. How do you use the Pythagorean Theorem to find the distance between two points?

Tip: When using the distance formula, remember that the order of subtraction doesn’t matter because the distance squared will eliminate any negative signs.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry

Formulas

Distance formula

Theorems

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Suitable Grade Level

Grades 7-9