Math Problem Statement

The is Compound interest Rs. 104 for 2 years is Rs.100 or the Same on a Certain Sum and simple interest period. Find the approximate difference bo Compound interest and simple interest of the Same Sum for 3 years

Solution

To solve this problem, we need to find the difference between compound interest (CI) and simple interest (SI) for a certain sum over 3 years. Given data includes:

  • Compound interest for 2 years: Rs. 104
  • Simple interest for 2 years on the same sum: Rs. 100

Step 1: Calculate the rate of interest per annum

We can use the relationship between CI and SI to find the rate of interest.

The formula for compound interest after 2 years (with annual compounding) is given by: A=P(1+R100)2A = P \left(1 + \frac{R}{100}\right)^2 Where:

  • AA is the amount after 2 years.
  • PP is the principal.
  • RR is the rate of interest.

The interest earned (CI) is: CI=APCI = A - P

The formula for simple interest is: SI=P×R×T100SI = \frac{P \times R \times T}{100} Where:

  • TT is the time in years.

Given that SI for 2 years is Rs. 100: P×R×2100=100\frac{P \times R \times 2}{100} = 100 P×R=5000P \times R = 5000

Step 2: Calculate Compound Interest for 3 years

Using the relation P×R=5000P \times R = 5000, we first need to find RR.

Now we can approximate the difference between the compound interest and simple interest over three years for same

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Simple Interest
Algebra

Formulas

Compound Interest formula: A = P (1 + R/100)^T
Simple Interest formula: SI = (P × R × T) / 100

Theorems

Basic Interest Calculation Theorem

Suitable Grade Level

Grades 8-10