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The problem states:

"The difference between simple interest on a certain sum of money for 2 years and 3 years at 10% per annum is ₹300. Find the sum."

### Step-by-step solution:

Let the principal amount (the sum) be \( P \).

The formula for simple interest (SI) is:
\[
SI = \frac{P \times R \times T}{100}
\]
Where:
- \( P \) is the principal amount.
- \( R \) is the rate of interest (10% in this case).
- \( T \) is the time in years.

#### Interest for 2 years:
\[
SI_2 = \frac{P \times 10 \times 2}{100} = \frac{P \times 20}{100} = 0.2P
\]

#### Interest for 3 years:
\[
SI_3 = \frac{P \times 10 \times 3}{100} = \frac{P \times 30}{100} = 0.3P
\]

#### Difference between the interests:
\[
SI_3 - SI_2 = 0.3P - 0.2P = 0.1P
\]

According to the problem, this difference is ₹300:
\[
0.1P = 300
\]

#### Solving for \( P \):
\[
P = \frac{300}{0.1} = 3000
\]

### Final answer:
The sum is **₹3000**.

---

Would you like more details or have any other questions about the solution? 

Here are 5 related questions for practice:
1. What would be the sum if the rate of interest were 5% instead of 10%?
2. How much simple interest would be earned on ₹3000 at 10% in 5 years?
3. What is the difference between the interest for 1 year and 2 years at 10% on ₹3000?
4. How would the principal change if the difference in interest was ₹400 instead of ₹300?
5. How would the interest change if the principal was doubled but the time and rate remained the same?

**Tip:** The key in simple interest problems is that the interest grows linearly with time. This makes it easy to compare changes over different time periods.

The difference between simple interest on a certain sum of money for 2 years and 3 years at 10% per annum is ₹300. Find the sum.

Learn how to solve a simple interest problem where the difference in interest over 2 and 3 years at 10% per annum is ₹300. This detailed solution involves basic algebra and simple interest formulas. Ideal for students in Grades 8-10.

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