Math Problem Statement

A boat crosses a 20 meter wide river with a steady current of 1.2 m/s. The boat's speed on the water is 3.4 m/s. At what angle relative to the current must the boat point to move across exactly perpendicular to the river?

Solution

To solve this problem, we need to find the angle at which the boat must point relative to the current to move directly across the river, perpendicular to the riverbanks. This is a classic example of vector addition, where the boat’s velocity through the water and the river's current combine to give the boat's resultant velocity.

Given:

  • Width of the river is 20 meters (but this is not necessary for solving the problem).
  • Speed of the river's current vr=1.2m/sv_r = 1.2 \, \text{m/s}.
  • Speed of the boat relative to the water vb=3.4m/sv_b = 3.4 \, \text{m/s}.

Step-by-Step Solution:

  1. Set up the velocity components:

    • The river current flows horizontally with a velocity vr=1.2m/sv_r = 1.2 \, \text{m/s}.
    • The boat's velocity relative to the water is vb=3.4m/sv_b = 3.4 \, \text{m/s}, and we are looking for the angle θ\theta at which the boat must point to cancel the effect of the current in the horizontal direction.
  2. Vector components: To move perpendicularly across the river, the horizontal component of the boat's velocity must cancel out the river's current. Thus, the horizontal component of the boat's velocity, which is vbsin(θ)v_b \cdot \sin(\theta), should exactly counter the current vrv_r: vbsin(θ)=vrv_b \cdot \sin(\theta) = v_r

  3. Solve for θ\theta: sin(θ)=vrvb=1.23.4\sin(\theta) = \frac{v_r}{v_b} = \frac{1.2}{3.4} sin(θ)0.3529\sin(\theta) \approx 0.3529 Now, find the angle θ\theta using the inverse sine function: θ=sin1(0.3529)20.66\theta = \sin^{-1}(0.3529) \approx 20.66^\circ

Conclusion:

The boat must point at an angle of approximately 20.6620.66^\circ upstream relative to the current to move directly across the river.

Would you like further clarification or details on any step?

Here are 5 related questions:

  1. How would the angle change if the river current increased to 2 m/s?
  2. What is the time taken to cross the river at this angle?
  3. What would happen if the boat did not compensate for the river's current?
  4. How do you compute the resultant velocity of the boat across the river?
  5. What would be the boat's angle if the boat’s speed on water was doubled?

Tip: Remember, vector addition is key when dealing with combined motion in two dimensions, especially in problems involving velocity and direction!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Vector Addition
Trigonometry
Velocity Components

Formulas

v_b * sin(θ) = v_r
sin(θ) = v_r / v_b
θ = sin^(-1)(v_r / v_b)

Theorems

Inverse Sine Function (sin⁻¹)
Right Triangle Trigonometry

Suitable Grade Level

Grades 10-12