https://file.aiquickdraw.com/mathbot/file/1728727195590mtfnwiv3.jpg

The given shape is a trapezium (or trapezoid), which has two parallel sides (the top and the bottom), and two non-parallel sides.

### To calculate the area of a trapezium:
The formula for the area of a trapezium is:
\[
A = \frac{1}{2} \times (a + b) \times h
\]
Where:
- \( a \) and \( b \) are the lengths of the parallel sides,
- \( h \) is the height (the perpendicular distance between the two parallel sides).

From the image:
- One of the parallel sides \( a = 16 \, \text{cm} \),
- The other parallel side \( b = 10 \, \text{cm} \),
- The height \( h = 19 \, \text{cm} \).

### Plugging the values into the formula:
\[
A = \frac{1}{2} \times (16 + 10) \times 19
\]
\[
A = \frac{1}{2} \times 26 \times 19
\]
\[
A = 13 \times 19 = 247 \, \text{cm}^2
\]

So, the area of the trapezium is **247 cm²**.

Would you like a breakdown of any step? 

Here are some related questions for further understanding:
1. How would you calculate the perimeter of this trapezium?
2. What happens if the height of the trapezium changes but the bases stay the same?
3. Can you find the height if only the area and the parallel sides are known?
4. How is the area formula for a trapezium derived?
5. How do you calculate the area of a trapezium if the height is missing?

**Tip:** The height in a trapezium is always the perpendicular distance between the parallel sides, not the slant height.

Work out the area of the trapezium below.

Learn how to find the area of a trapezium with given dimensions: parallel sides 16 cm and 10 cm, and height 19 cm. This problem covers essential geometry concepts, including the formula for trapezium area. Suitable for students in Grades 7-9.

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