Math Problem Statement

Work out the area of the trapezium below.

Solution

The given shape is a trapezium (or trapezoid), which has two parallel sides (the top and the bottom), and two non-parallel sides.

To calculate the area of a trapezium:

The formula for the area of a trapezium is: A=12×(a+b)×hA = \frac{1}{2} \times (a + b) \times h Where:

  • aa and bb are the lengths of the parallel sides,
  • hh is the height (the perpendicular distance between the two parallel sides).

From the image:

  • One of the parallel sides a=16cma = 16 \, \text{cm},
  • The other parallel side b=10cmb = 10 \, \text{cm},
  • The height h=19cmh = 19 \, \text{cm}.

Plugging the values into the formula:

A=12×(16+10)×19A = \frac{1}{2} \times (16 + 10) \times 19 A=12×26×19A = \frac{1}{2} \times 26 \times 19 A=13×19=247cm2A = 13 \times 19 = 247 \, \text{cm}^2

So, the area of the trapezium is 247 cm².

Would you like a breakdown of any step?

Here are some related questions for further understanding:

  1. How would you calculate the perimeter of this trapezium?
  2. What happens if the height of the trapezium changes but the bases stay the same?
  3. Can you find the height if only the area and the parallel sides are known?
  4. How is the area formula for a trapezium derived?
  5. How do you calculate the area of a trapezium if the height is missing?

Tip: The height in a trapezium is always the perpendicular distance between the parallel sides, not the slant height.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of Trapezium
Measurement

Formulas

A = (1/2) × (a + b) × h

Theorems

Trapezium Area Formula

Suitable Grade Level

Grades 7-9