https://file.aiquickdraw.com/mathbot/file/1729095915136z4e6qrue.jpg

To calculate the area of the trapezium (trapezoid), we use the formula:

\[
\text{Area} = \frac{1}{2} \times (a + b) \times h
\]

Where:
- \(a\) and \(b\) are the lengths of the parallel sides (the two bases),
- \(h\) is the height (the perpendicular distance between the parallel sides).

From the image:
- \(a = 7 \, \text{cm}\),
- \(b = 9 \, \text{cm}\),
- \(h = 6 \, \text{cm}\).

Now, substituting these values into the formula:

\[
\text{Area} = \frac{1}{2} \times (7 + 9) \times 6 = \frac{1}{2} \times 16 \times 6 = 48 \, \text{cm}^2
\]

Therefore, the area of the trapezium is **48 cm²**.

Would you like more details or have any further questions? Here are five related questions to explore:

1. How do you calculate the perimeter of a trapezium?
2. What is the difference between a trapezium and a parallelogram?
3. How can you calculate the height of a trapezium if only the area and bases are given?
4. Can this formula for the area of a trapezium be used for other quadrilaterals?
5. What are the properties of an isosceles trapezium?

**Tip**: Always double-check that the given dimensions are in the same units when calculating areas!

Work out the area of the trapezium with parallel sides of 7 cm and 9 cm, and a height of 6 cm.

Learn how to calculate the area of a trapezium with parallel sides of 7 cm and 9 cm, and a height of 6 cm. This problem involves the trapezium area formula and is suitable for students in Grades 6-8. The final area is calculated to be 48 cm².

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