To calculate the area of this triangle, we can use the formula for the area of a right triangle:

$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$

Here:

• The base of the triangle is $8 \, \text{m}$.
• The height of the triangle is $6 \, \text{m}$.

Plugging these values into the formula:

$\text{Area} = \frac{1}{2} \times 8 \, \text{m} \times 6 \, \text{m} = \frac{1}{2} \times 48 \, \text{m}^2 = 24 \, \text{m}^2$

Answer: The area of the triangle is $24 \, \text{m}^2$.

Would you like further details or have any questions?

Here are five related questions that you may find helpful:

1. How do we calculate the area of a triangle that is not a right triangle?
2. What other properties can we find for this triangle, such as perimeter?
3. How would the area calculation change if the triangle’s shape or dimensions were different?
4. How can we determine the type of triangle if only given side lengths?
5. How can trigonometry be used to find angles in a triangle with given side lengths?

Tip: In right triangles, identifying the base and height simplifies area calculations significantly because they correspond to the two sides forming the right angle.