To calculate the angular momentum ($L$) of the top, we can use the formula:

$L = m \cdot v \cdot r$

where:

• $m$ is the mass of the top,
• $v$ is the linear velocity,
• $r$ is the radius of the circular path.

Given:

• Mass $m = 0.02 \, \text{kg}$
• Linear velocity $v = 2.41 \, \text{m/s}$
• Diameter of the circle = 10.2 cm = 0.102 m, thus the radius $r = \frac{0.102}{2} = 0.051 \, \text{m}$

Calculation:

Now we can plug in the values:

$L = 0.02 \, \text{kg} \cdot 2.41 \, \text{m/s} \cdot 0.051 \, \text{m}$

Calculating this:

$L = 0.02 \cdot 2.41 \cdot 0.051$ $L = 0.00244842 \, \text{kg m}^2/\text{s}$

Result:

The angular momentum of the top is approximately $0.00245 \, \text{kg m}^2/\text{s}$.

Would you like further details on this calculation or have any questions? Here are some related questions for your consideration:

1. How does the angle of lean affect the stability of the top?
2. What other factors can influence the angular momentum of a spinning object?
3. How would the angular momentum change if the top were spinning faster?
4. What is the relationship between linear velocity and angular velocity?
5. Can you explain the concept of moment of inertia and its role in angular momentum?

Tip: Remember that angular momentum is a vector quantity and has both magnitude and direction, which can change depending on the rotation axis.