We need to calculate the size of angle $y$ in the given triangle, using trigonometry. The rectangle is divided diagonally, forming a right triangle.

Step-by-step solution:

1. Label the triangle:

   • The base is $52.2 \, \text{cm}$ (adjacent to $y$).
   • The height is $29.4 \, \text{cm}$ (opposite to $y$).
   • The diagonal forms the hypotenuse.

2. Use the tangent function: $\tan(y) = \frac{\text{opposite}}{\text{adjacent}} = \frac{29.4}{52.2}$

3. Calculate $\tan(y)$: $\tan(y) = \frac{29.4}{52.2} \approx 0.5634$

4. Find $y$: Use the inverse tangent ($\arctan$) to calculate $y$: $y = \arctan(0.5634)$

   Using a calculator: $y \approx 29.4^\circ$

5. Final answer (to 1 decimal place): $y = 29.4^\circ$

Let me know if you want a detailed breakdown of any step or further explanation!

Related Questions:

1. What is the length of the diagonal of the rectangle?
2. How would the angle $y$ change if the base was shorter?
3. What is the area of the triangle formed by cutting the rectangle?
4. How can we verify the result using the Pythagorean theorem?
5. What trigonometric function can be used if the hypotenuse was known?

Tip: Always sketch the triangle and label its sides before applying trigonometric rules. It helps visualize the relationships clearly.