Math Problem Statement

Let R be a relation of set A of people. R={(a, b) : a is brother of b}. Is it an equivalence relation? Is R partial ordering? (discard half brother, paternity brother)

Solution

Let's analyze the relation RR on a set AA of people, where R={(a,b):a is the brother of b}R = \{(a, b) : a \text{ is the brother of } b \}, under the assumption that we are only considering full brothers, and excluding half-brothers and paternity brothers.

1. Equivalence Relation

To determine if RR is an equivalence relation, we need to check if it satisfies the following three properties:

a. Reflexive:

A relation RR is reflexive if (a,a)R(a, a) \in R for every aAa \in A. This means that each person must be the brother of himself.

  • However, no person is typically considered their own brother, so reflexivity does not hold.

b. Symmetric:

A relation RR is symmetric if (a,b)R(a, b) \in R implies (b,a)R(b, a) \in R. This means if aa is the brother of bb, then bb must also be the brother of aa.

  • If aa is the brother of bb, it naturally follows that bb is also the brother of aa. Therefore, symmetry holds.

c. Transitive:

A relation RR is transitive if (a,b)R(a, b) \in R and (b,c)R(b, c) \in R implies (a,c)R(a, c) \in R. This means if aa is the brother of bb, and bb is the brother of cc, then aa must also be the brother of cc.

  • Transitivity does not hold in this case, because if aa is the brother of bb and bb is the brother of cc, it does not necessarily mean that aa is the brother of cc (they could be cousins or unrelated in some other way). Hence, transitivity does not hold.

Since the relation fails to be reflexive and transitive, RR is not an equivalence relation.

2. Partial Ordering

A relation is a partial ordering if it is:

a. Reflexive:

As mentioned above, the relation is not reflexive because no one is considered their own brother.

b. Antisymmetric:

A relation is antisymmetric if (a,b)R(a, b) \in R and (b,a)R(b, a) \in R implies a=ba = b. This means if aa is the brother of bb, and bb is the brother of aa, then aa and bb must be the same person.

  • Antisymmetry does not hold, because two distinct people can be brothers. Therefore, antisymmetry fails.

c. Transitive:

As mentioned earlier, transitivity also does not hold.

Since RR is neither reflexive, antisymmetric, nor transitive, RR is not a partial ordering.

Conclusion:

  • RR is not an equivalence relation.
  • RR is not a partial ordering.

Would you like to go into more details about any part of this analysis?

Here are 5 related questions to deepen understanding:

  1. What is an example of a relation that is both symmetric and transitive but not reflexive?
  2. Can you provide an example of a partial ordering relation in everyday life?
  3. How would you define a strict partial ordering, and how does it differ from a regular partial ordering?
  4. In what ways can we modify this relation to make it an equivalence relation?
  5. How do equivalence relations partition a set, and can you give a real-world example?

Tip: Remember that partial orderings often arise in hierarchies or systems where some elements are comparable, but not all (e.g., family trees, job titles).

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Math Problem Analysis

Mathematical Concepts

Set Theory
Relations
Equivalence Relations
Partial Ordering

Formulas

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Theorems

Reflexive Property
Symmetric Property
Transitive Property
Antisymmetric Property

Suitable Grade Level

Undergraduate Level