The formula for blood flow rate is given by 𝑭 =
𝒑𝟏−𝒑𝟐
𝒓
, where 𝐹 is the flow rate, 𝑝1 is the 
initial pressure, 𝑝2 is the final pressure, and 𝑟 is the resistance created by blood vessel size.
a) Classify the given equation whether it is one – step, two – step, absolute value or literal 
equation and mention the reason. 
b) Use the formula to find the blood flow rate 𝐹 given that the initial pressure is 80, the 
final pressure is 60, and the resistance created by blood vessel is 5.
c) Solve the given formula for 𝑝1.
d) Use the resulting formula in c) to find the value of 𝑝1 if 𝐹 = 5, 𝑝2 = 70 𝑎𝑛𝑑 𝑟 = 4
e) Resolve the given formula for 𝑟.

Let's work through each part step-by-step:

### Part (a)
The given equation is:
\[
F = \frac{p_1 - p_2}{r}
\]

1. **Classification**: This is a **literal equation**.
   - **Reason**: A literal equation is an equation with multiple variables, where no specific numerical values are provided, and it is typically solved for one variable in terms of the others. In this case, \(F\), \(p_1\), \(p_2\), and \(r\) are all variables.

### Part (b)
We need to calculate the flow rate \( F \) using the values:
- \( p_1 = 80 \)
- \( p_2 = 60 \)
- \( r = 5 \)

Substitute these values into the formula:
\[
F = \frac{p_1 - p_2}{r} = \frac{80 - 60}{5} = \frac{20}{5} = 4
\]

So, the blood flow rate \( F \) is:
\[
F = 4
\]

### Part (c)
To solve for \( p_1 \) in terms of \( F \), \( p_2 \), and \( r \), start with the equation:
\[
F = \frac{p_1 - p_2}{r}
\]

Multiply both sides by \( r \) to isolate \( p_1 - p_2 \):
\[
F \cdot r = p_1 - p_2
\]

Then, add \( p_2 \) to both sides:
\[
p_1 = F \cdot r + p_2
\]

Thus, the formula for \( p_1 \) is:
\[
p_1 = F \cdot r + p_2
\]

### Part (d)
Using the formula for \( p_1 \) derived in part (c), find \( p_1 \) when:
- \( F = 5 \)
- \( p_2 = 70 \)
- \( r = 4 \)

Substitute these values into the formula:
\[
p_1 = F \cdot r + p_2 = 5 \cdot 4 + 70 = 20 + 70 = 90
\]

So, the value of \( p_1 \) is:
\[
p_1 = 90
\]

### Part (e)
To solve for \( r \) in terms of \( F \), \( p_1 \), and \( p_2 \), start with the original equation:
\[
F = \frac{p_1 - p_2}{r}
\]

Multiply both sides by \( r \) and then divide by \( F \) to isolate \( r \):
\[
r = \frac{p_1 - p_2}{F}
\]

Thus, the formula for \( r \) is:
\[
r = \frac{p_1 - p_2}{F}
\]

Would you like further details on any part?

---

### Related Questions
1. What are literal equations, and how are they used in real-world applications?
2. How can you classify other types of equations, such as absolute value or quadratic equations?
3. Why does resistance affect blood flow rate, and how does it relate to health?
4. How would changing \( p_1 \) or \( p_2 \) impact the blood flow rate?
5. How does this formula relate to Ohm's Law in physics?

#### Tip:
When rearranging formulas, always perform the same operation on both sides of the equation to keep it balanced.

The formula for blood flow rate is given by 𝑭 = 𝒑𝟏−𝒑𝟐 / 𝒓, where 𝐹 is the flow rate, 𝑝1 is the initial pressure, 𝑝2 is the final pressure, and 𝑟 is the resistance created by blood vessel size. a) Classify the given equation whether it is one–step, two–step, absolute value or literal equation and mention the reason. b) Use the formula to find the blood flow rate 𝐹 given that the initial pressure is 80, the final pressure is 60, and the resistance created by blood vessel is 5. c) Solve the given formula for 𝑝1. d) Use the resulting formula in c) to find the value of 𝑝1 if 𝐹 = 5, 𝑝2 = 70 and 𝑟 = 4. e) Resolve the given formula for 𝑟.

This solution explains how to classify and solve the blood flow rate equation F = (p1 - p2) / r. Explore how to find flow rate, rearrange for variables, and apply given values for initial pressure, final pressure, and resistance. Ideal for students in Grades 8-10.

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