Math Problem Statement

Blood plasma (at 37.0°C) is to be supplied to a patient at the rate of 2.80 × 10−6 m3/s. If the tube connecting the plasma to the patient’s vein has a radius of 2.00 mm and a length of 54.0 cm, what is the pressure difference between the plasma and the patient’s vein? Viscosity of blood plasma is 1.30 × 10−3 Pa·s.

Solution

To solve for the pressure difference required to supply blood plasma through a tube at a certain flow rate, we can use Poiseuille’s Law for laminar flow, which is:

ΔP=8ηQLπr4\Delta P = \frac{8 \eta Q L}{\pi r^4}

where:

  • ΔP\Delta P = pressure difference (what we want to find),
  • η\eta = viscosity of the fluid (given as 1.30×103Pas1.30 \times 10^{-3} \, \text{Pa} \cdot \text{s}),
  • QQ = volumetric flow rate (given as 2.80×106m3/s2.80 \times 10^{-6} \, \text{m}^3/\text{s}),
  • LL = length of the tube (given as 54.0 cm, or 0.54 m),
  • rr = radius of the tube (given as 2.00 mm, or 0.002 m).

Step 1: Substitute the values into Poiseuille’s equation

ΔP=8(1.30×103)(2.80×106)0.54π(0.002)4\Delta P = \frac{8 \cdot (1.30 \times 10^{-3}) \cdot (2.80 \times 10^{-6}) \cdot 0.54}{\pi \cdot (0.002)^4}

Step 2: Calculate each term

1. Calculate r4r^4

r4=(0.002)4=1.6×1011m4r^4 = (0.002)^4 = 1.6 \times 10^{-11} \, \text{m}^4

2. Calculate the numerator

8(1.30×103)(2.80×106)0.54=1.57056×1088 \cdot (1.30 \times 10^{-3}) \cdot (2.80 \times 10^{-6}) \cdot 0.54 = 1.57056 \times 10^{-8}

3. Substitute and solve for ΔP\Delta P

ΔP=1.57056×108π1.6×1011\Delta P = \frac{1.57056 \times 10^{-8}}{\pi \cdot 1.6 \times 10^{-11}}

ΔP=1.57056×1085.0265×1011\Delta P = \frac{1.57056 \times 10^{-8}}{5.0265 \times 10^{-11}}

ΔP312.4Pa\Delta P \approx 312.4 \, \text{Pa}

Answer

The pressure difference required to supply blood plasma at the given rate is approximately:

ΔP312.4Pa\Delta P \approx 312.4 \, \text{Pa}

Would you like more details on any of these steps?


  1. How would changes in the viscosity affect the pressure difference?
  2. How would altering the radius impact the flow rate or pressure difference?
  3. What assumptions are made when using Poiseuille's Law for blood plasma flow?
  4. How would temperature variations affect blood plasma viscosity?
  5. Could this calculation apply to other fluids besides blood plasma?

Tip: Always ensure units are consistent in physics equations; small discrepancies can lead to significant errors in results.

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Math Problem Analysis

Mathematical Concepts

Fluid Dynamics
Laminar Flow
Pressure Difference

Formulas

Poiseuille's Law: ΔP = (8ηQL) / (πr^4)

Theorems

Poiseuille's Law

Suitable Grade Level

Grades 11-12