Math Problem Statement

If {1,2,3,4,5,6,7,8} U is universal set. Let {1,2,4,6} A and {2,3,5,7} B be two subsets of U. Then, find bit string of A, B, c A , c B A B  , A B  , c A B  , c B A  , c A B  , c c A B  and ( )c A

Solution

Given that the universal set is U={1,2,3,4,5,6,7,8}U = \{1, 2, 3, 4, 5, 6, 7, 8\}, we are asked to represent the sets AA, BB, and their complements and intersections in terms of bit strings. A bit string uses 0 or 1 to indicate the absence or presence of elements corresponding to their positions in the universal set.

Let’s break it down and find the bit strings for each set and operation:

Step 1: Bit Strings for A, B, and Complements

  • Universal set UU has 8 elements, so the bit strings will be 8 bits long.

  • Set A={1,2,4,6}A = \{1, 2, 4, 6\}:

    • AA includes elements 1, 2, 4, and 6. In terms of a bit string, this is:
      A=11010100A = 11010100
      (1s at positions corresponding to 1, 2, 4, and 6, and 0s elsewhere).
  • Set B={2,3,5,7}B = \{2, 3, 5, 7\}:

    • BB includes elements 2, 3, 5, and 7. In terms of a bit string, this is:
      B=01101010B = 01101010
      (1s at positions corresponding to 2, 3, 5, and 7, and 0s elsewhere).
  • Complement of AA (AcA^c):

    • AcA^c includes all elements not in AA, which are {3,5,7,8}\{3, 5, 7, 8\}. The bit string for AcA^c is:
      Ac=00101011A^c = 00101011.
  • Complement of BB (BcB^c):

    • BcB^c includes all elements not in BB, which are {1,4,6,8}\{1, 4, 6, 8\}. The bit string for BcB^c is:
      Bc=10010101B^c = 10010101.

Step 2: Set Operations

  • Union of AA and BB (ABA \cup B):

    • The union includes elements that are in either AA or BB. The bit string for ABA \cup B is:
      AB=11111110A \cup B = 11111110.
  • Intersection of AA and BB (ABA \cap B):

    • The intersection includes elements that are in both AA and BB. The bit string for ABA \cap B is:
      AB=01000000A \cap B = 01000000.
  • Union of complement of AA and BB (AcBA^c \cup B):

    • This operation includes elements that are in AcA^c or BB. The bit string for AcBA^c \cup B is:
      AcB=01101011A^c \cup B = 01101011.
  • Union of complement of BB and AA (BcAB^c \cup A):

    • This operation includes elements that are in BcB^c or AA. The bit string for BcAB^c \cup A is:
      BcA=11010101B^c \cup A = 11010101.
  • Union of complement of AA and complement of BB (AcBcA^c \cup B^c):

    • This operation includes elements that are in AcA^c or BcB^c. The bit string for AcBcA^c \cup B^c is:
      AcBc=10111111A^c \cup B^c = 10111111.
  • Complement of intersection of AA and BB ((AB)c(A \cap B)^c):

    • The complement of the intersection is the set of elements not in ABA \cap B. The bit string for (AB)c(A \cap B)^c is:
      (AB)c=10111111(A \cap B)^c = 10111111.

Summary of Bit Strings

  1. A=11010100A = 11010100
  2. B=01101010B = 01101010
  3. Ac=00101011A^c = 00101011
  4. Bc=10010101B^c = 10010101
  5. AB=11111110A \cup B = 11111110
  6. AB=01000000A \cap B = 01000000
  7. AcB=01101011A^c \cup B = 01101011
  8. BcA=11010101B^c \cup A = 11010101
  9. AcBc=10111111A^c \cup B^c = 10111111
  10. (AB)c=10111111(A \cap B)^c = 10111111

Would you like more details on any step?
Here are some related questions:

  1. How is the complement of a set represented in terms of a bit string?
  2. What is the general approach for finding the union of two sets using bit strings?
  3. How do you find the intersection of two sets using bit strings?
  4. Can you explain how to compute the complement of a union or intersection using De Morgan’s laws?
  5. How does the universal set affect the length of bit strings?

Tip: The union of sets corresponds to the logical "OR" operation, while the intersection corresponds to the logical "AND" operation on bit strings.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Bit Strings
Complement
Union
Intersection

Formulas

Bit string representation: 1 for presence of element, 0 for absence
Complement: A^c = U - A
Union: A ∪ B = {x | x ∈ A or x ∈ B}
Intersection: A ∩ B = {x | x ∈ A and x ∈ B}

Theorems

De Morgan's Laws

Suitable Grade Level

Grades 9-12