Math Problem Statement

If {1,2,3,4,5,6,7,8} U is universal set. Let {1,2,4,6} A and {2,3,5,7} B be two subsets of U. Then, find bit string of A, B, c A , c B A B  , A B  , c A B  , c B A  , c A B  , c c A B  and ( )c A

Solution

Given the universal set U={1,2,3,4,5,6,7,8}U = \{1, 2, 3, 4, 5, 6, 7, 8\}, subsets A={1,2,4,6}A = \{1, 2, 4, 6\} and B={2,3,5,7}B = \{2, 3, 5, 7\}, we need to represent the following sets as bit strings relative to UU:

1. Bit string representation

A bit string uses the order of the elements in UU to represent whether an element is in the subset (1) or not (0).

Universal Set (U): U={1,2,3,4,5,6,7,8}U = \{1, 2, 3, 4, 5, 6, 7, 8\} Positions: 1,2,3,4,5,6,7,81, 2, 3, 4, 5, 6, 7, 8

  • A: A={1,2,4,6}A = \{1, 2, 4, 6\} A bit string:11010100A \text{ bit string}: 11010100

  • B: B={2,3,5,7}B = \{2, 3, 5, 7\} B bit string:01101010B \text{ bit string}: 01101010

2. Complement of A (AcA^c)

The complement of AA contains all elements of UU that are not in AA.

Ac={3,5,7,8}A^c = \{3, 5, 7, 8\} Ac bit string:00101011A^c \text{ bit string}: 00101011

3. Complement of B (BcB^c)

The complement of BB contains all elements of UU that are not in BB.

Bc={1,4,6,8}B^c = \{1, 4, 6, 8\} Bc bit string:10010101B^c \text{ bit string}: 10010101

4. Union of A and B (ABA \cup B)

The union of AA and BB includes all elements that are in either AA or BB (or both).

AB={1,2,3,4,5,6,7}A \cup B = \{1, 2, 3, 4, 5, 6, 7\} AB bit string:11111110A \cup B \text{ bit string}: 11111110

5. Intersection of A and B (ABA \cap B)

The intersection of AA and BB includes only the elements that are in both AA and BB.

AB={2}A \cap B = \{2\} AB bit string:01000000A \cap B \text{ bit string}: 01000000

6. Union of the complement of A and B (AcBA^c \cup B)

AcB={1,2,3,5,7,8}A^c \cup B = \{1, 2, 3, 5, 7, 8\} AcB bit string:11101011A^c \cup B \text{ bit string}: 11101011

7. Union of the complement of B and A (BcAB^c \cup A)

BcA={1,2,4,6,8}B^c \cup A = \{1, 2, 4, 6, 8\} BcA bit string:11010101B^c \cup A \text{ bit string}: 11010101

8. Union of complements of A and B (AcBcA^c \cup B^c)

AcBc={1,3,4,5,6,7,8}A^c \cup B^c = \{1, 3, 4, 5, 6, 7, 8\} AcBc bit string:10111111A^c \cup B^c \text{ bit string}: 10111111

9. Complement of the union of A and B ((AB)c(A \cup B)^c)

The complement of the union of AA and BB includes all elements of UU that are not in ABA \cup B.

(AB)c={8}(A \cup B)^c = \{8\} (AB)c bit string:00000001(A \cup B)^c \text{ bit string}: 00000001

Final Answers:

  1. AA: 11010100
  2. BB: 01101010
  3. AcA^c: 00101011
  4. BcB^c: 10010101
  5. ABA \cup B: 11111110
  6. ABA \cap B: 01000000
  7. AcBA^c \cup B: 11101011
  8. BcAB^c \cup A: 11010101
  9. AcBcA^c \cup B^c: 10111111
  10. (AB)c(A \cup B)^c: 00000001

Would you like further clarification or details on any of these operations?

Here are 5 related questions for you to consider:

  1. How can bit strings be used to represent larger sets efficiently?
  2. What is the relationship between set operations and logical operations in computer science?
  3. Can you find the intersection of the complements AcBcA^c \cap B^c?
  4. How would the bit string representation change if UU had more elements?
  5. Can you find the symmetric difference AΔBA \Delta B and its bit string?

Tip: Understanding set operations in terms of bit strings is crucial in areas like digital logic and computer networks.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Bit Strings
Set Operations
Union
Intersection
Complement

Formulas

Bit String Representation: Use 1 for elements in the set and 0 for elements not in the set.
Union: A ∪ B = {x | x ∈ A or x ∈ B}
Intersection: A ∩ B = {x | x ∈ A and x ∈ B}
Complement: Ac = U - A

Theorems

De Morgan's Laws
Basic Set Operations

Suitable Grade Level

Grades 9-12