Math Problem Statement

Suppose you have X ∼ Binom(n, p) where n is known and p is unknown. Typically, people use bp = X1 n to estimate p, where X = X1 is simply a sample of size 1. (Note: A sample of size 1 from a Binomial RV is equivalent to n Bernoulli trials.) This might represent simultaneously flipping n coins (just once!) and counting the number of heads you see, where each coin has pheads = p. Now, if both n and p are known, we know the variance, V , of X is just np(1 − p). If p is unknown, you might want to estimate V using the estimator bV = n  X1 n   1 − X1 n  . Find the bias of bV , and if it is biased, determine if it is asymptotically unbiased, and also modify bV to create a new unbiased estimator

Solution

We are given that XBinom(n,p)X \sim \text{Binom}(n, p) and that an estimator for pp is

p^=Xn\hat{p} = \frac{X}{n}

where XX is a single sample from the binomial distribution.

The variance of XX is known to be

V(X)=np(1p).V(X) = np(1 - p).

The given estimator for V(X)V(X) is:

V^=np^(1p^)=n(Xn)(1Xn)=Xn(nX).\hat{V} = n \hat{p} (1 - \hat{p}) = n \left(\frac{X}{n}\right) \left(1 - \frac{X}{n}\right) = \frac{X}{n} (n - X).

Step 1: Compute the Expected Value of V^\hat{V}

To determine whether V^\hat{V} is biased, we compute its expectation:

[ E[\hat{V}] = E \left[ \frac{X}{n} (n - X) \right]. ]

Expanding,

[ E[\hat{V}] = \frac{1}{n} E[X(n - X)]. ]

Using the properties of expectation,

[ E[X(n - X)] = nE[X] - E[X^2]. ]

Since XBinom(n,p)X \sim \text{Binom}(n, p), we know:

E[X]=np.E[X] = np.

For E[X2]E[X^2], we use the second moment formula for a binomial variable:

[ E[X^2] = V(X) + (E[X])^2 = np(1 - p) + (np)^2. ]

Thus,

[ E[X(n - X)] = n(np) - \left[ np(1 - p) + (np)^2 \right]. ]

Simplifying,

E[X(nX)]=n2pnpnp2n+np.E[X(n - X)] = n^2p - np - np^2n + np.

=n2p(1p).= n^2p(1 - p).

Dividing by nn, we get:

E[V^]=n2p(1p)n=(n1)p(1p).E[\hat{V}] = \frac{n^2p(1 - p)}{n} = (n - 1)p(1 - p).

Step 2: Bias of V^\hat{V}

Since the true variance is np(1p)np(1 - p), we compute the bias:

Bias(V^)=E[V^]V(X)=(n1)p(1p)np(1p).\text{Bias}(\hat{V}) = E[\hat{V}] - V(X) = (n - 1)p(1 - p) - np(1 - p).

=np(1p)p(1p)=p(1p).= np(1 - p) - p(1 - p) = -p(1 - p).

Thus, V^\hat{V} is biased.

Step 3: Asymptotic Unbiasedness

Since

limnE[V^]V(X)=limn(n1)p(1p)np(1p)=limnn1n=1,\lim_{n \to \infty} \frac{E[\hat{V}]}{V(X)} = \lim_{n \to \infty} \frac{(n - 1)p(1 - p)}{np(1 - p)} = \lim_{n \to \infty} \frac{n - 1}{n} = 1,

we conclude that V^\hat{V} is asymptotically unbiased.

Step 4: Unbiased Estimator

To construct an unbiased estimator, we use the fact that the expectation of V^\hat{V} is (n1)p(1p)(n - 1)p(1 - p), whereas the true variance is np(1p)np(1 - p). To correct this bias, we scale V^\hat{V} by nn1\frac{n}{n - 1}:

V^unbiased=nn1V^.\hat{V}_{\text{unbiased}} = \frac{n}{n - 1} \hat{V}.

Thus, the final unbiased estimator for V(X)V(X) is:

V^unbiased=nn1Xn(nX)=X(nX)n1.\hat{V}_{\text{unbiased}} = \frac{n}{n - 1} \cdot \frac{X}{n} (n - X) = \frac{X(n - X)}{n - 1}.


Summary:

  1. The given estimator V^=Xn(nX)\hat{V} = \frac{X}{n} (n - X) is biased.

  2. The bias is p(1p)-p(1 - p), meaning it systematically underestimates the variance.

  3. The estimator is asymptotically unbiased as nn \to \infty.

  4. An unbiased estimator can be obtained by scaling V^\hat{V} by nn1\frac{n}{n - 1}, resulting in:

    V^unbiased=X(nX)n1.\hat{V}_{\text{unbiased}} = \frac{X(n - X)}{n - 1}.

Would you like further clarification on any step?


Related Questions:

  1. How do you derive the expectation of X2X^2 for a binomial variable?
  2. Why does the estimator become unbiased as nn \to \infty?
  3. How does this method compare to variance estimation in other distributions?
  4. What other methods exist to estimate the variance of a binomial distribution?
  5. How does bias affect statistical inference in practical applications?

Tip: In statistical estimation, a common trick to remove bias is multiplying the biased estimator by a correction factor derived from expectation calculations.

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Math Problem Analysis

Mathematical Concepts

Binomial Distribution
Expectation
Variance
Statistical Estimation
Bias

Formulas

E[X] = np
E[X^2] = np(1 - p) + (np)^2
V(X) = np(1 - p)
E[\hat{V}] = (n - 1)p(1 - p)
Bias(\hat{V}) = -p(1 - p)
\hat{V}_{\text{unbiased}} = \frac{X(n - X)}{n - 1}

Theorems

Bias of an Estimator
Asymptotic Unbiasedness
Unbiased Estimator Construction

Suitable Grade Level

Undergraduate (Advanced Statistics)