Math Problem Statement

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n independent trials of the experiment. n equals 12​, p equals 0.4​, x less than or equals 4 Question content area bottom Part 1 The probability of x less than or equals 4 successes is    enter your response here. ​(Round to four decimal places as​ needed.)

Solution

The binomial probability formula is given by:

P(X=x)=(nx)px(1p)nxP(X = x) = \binom{n}{x} p^x (1 - p)^{n - x}

Where:

  • nn = 12 (number of trials)
  • pp = 0.4 (probability of success)
  • x4x \leq 4 (we want the cumulative probability for x=0,1,2,3,4x = 0, 1, 2, 3, 4)

The cumulative probability of x4x \leq 4 is the sum of the probabilities for x=0,1,2,3,4x = 0, 1, 2, 3, 4:

P(X4)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Let’s compute these probabilities step by step. I'll calculate this now.The probability of getting x4x \leq 4 successes in 12 independent trials, with a probability of success p=0.4p = 0.4, is approximately 0.4382 (rounded to four decimal places).

Do you have any questions or would you like further details on this?

Here are five related questions you might find useful:

  1. How does changing pp affect the binomial distribution?
  2. What happens to the probability when nn increases?
  3. How do we calculate the mean and variance of a binomial distribution?
  4. What is the probability of exactly 4 successes in this experiment?
  5. How does the binomial distribution differ from the normal distribution?

Tip: The mean of a binomial distribution is μ=np\mu = np, and the variance is σ2=np(1p)\sigma^2 = np(1 - p).

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Math Problem Analysis

Mathematical Concepts

Binomial Distribution
Probability Theory

Formulas

P(X = x) = C(n, x) * p^x * (1 - p)^(n - x)
P(X ≤ x) = Sum of P(X = k) for k = 0 to x

Theorems

Binomial Theorem

Suitable Grade Level

Grades 10-12