Math Problem Statement

give me the answer like mathmetical turm not theorytical and all so be with diagram

Write the Breadth-First search (BFS) algorithm and use BFS algorithm to find a spanning tree of the graph.

Solution

To solve this problem, we need to apply the Breadth-First Search (BFS) algorithm to find a spanning tree for the given graph. I'll break down the solution in mathematical terms and provide a step-by-step outline of how BFS would build the spanning tree from a selected starting node.

Given the structure of BFS, we'll start at a specific node (let's choose node aa as the root) and traverse level by level, visiting each neighboring node before moving to the next level.

Step-by-Step BFS Solution with the Graph

  1. Start at Node aa:

    • Visited nodes: aa
    • Queue: aa
  2. Visit neighbors of aa:

    • Neighbors of aa are bb, ee, and dd.
    • Add bb, ee, and dd to the queue and mark them as visited.
    • Edges selected: (a,b)(a, b), (a,e)(a, e), (a,d)(a, d)
    • Visited nodes: a,b,e,da, b, e, d
    • Queue: b,e,db, e, d
  3. Visit neighbors of bb:

    • Neighbors of bb are aa, ee, and cc.
    • aa and ee are already visited, so we add cc to the queue.
    • Edge selected: (b,c)(b, c)
    • Visited nodes: a,b,e,d,ca, b, e, d, c
    • Queue: e,d,ce, d, c
  4. Visit neighbors of ee:

    • Neighbors of ee are aa, bb, cc, and dd.
    • All neighbors aa, bb, cc, and dd are already visited, so no new nodes are added.
    • Queue: d,cd, c
  5. Visit neighbors of dd:

    • Neighbors of dd are aa and ee.
    • Both neighbors aa and ee are already visited, so no new nodes are added.
    • Queue: cc
  6. Visit neighbors of cc:

    • Neighbors of cc are bb and ee.
    • Both neighbors bb and ee are already visited, so no new nodes are added.
    • Queue: (empty)

At this point, all nodes have been visited, and the edges selected form a spanning tree.

Resulting Spanning Tree

The edges in the spanning tree obtained through BFS from node aa are: (a,b),(a,e),(a,d),(b,c)(a, b), (a, e), (a, d), (b, c)

Spanning Tree Diagram

The spanning tree structure can be drawn as follows (edges used are highlighted):

  • Node aa connects to bb, ee, and dd.
  • Node bb connects to cc.

This forms a connected, acyclic graph that spans all vertices, meeting the requirements of a spanning tree.


Would you like a visual representation of this spanning tree?

Related Questions:

  1. How would the BFS traversal change if we started from a different node, like bb?
  2. What are the key differences between BFS and Depth-First Search (DFS) in terms of resulting spanning trees?
  3. How does BFS guarantee finding the shortest path in an unweighted graph?
  4. Can BFS be applied to weighted graphs, and what modifications are necessary?
  5. How can we verify if the edges obtained indeed form a tree?

Tip:

In BFS, always process each level of neighbors before moving to the next to ensure the shortest-path characteristic in an unweighted graph.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Graph Theory
Breadth-First Search (BFS)
Spanning Tree

Formulas

-

Theorems

-

Suitable Grade Level

Undergraduate Level