Math Problem Statement

In the graph of y= tanX , if x approach to Pai/2 + , then tanX = ?

Solution

In the graph of y=tan(x)y = \tan(x), the behavior of the function as xπ2+x \to \frac{\pi}{2}^+ can be analyzed using the properties of the tangent function.

Key Insight:

  • The tangent function, tan(x)=sin(x)cos(x)\tan(x) = \frac{\sin(x)}{\cos(x)}, has vertical asymptotes at x=π2+nπx = \frac{\pi}{2} + n\pi (where nZn \in \mathbb{Z}).
  • Near x=π2+x = \frac{\pi}{2}^+, the denominator cos(x)\cos(x) approaches 00 from the negative side (since cos(x)\cos(x) transitions from positive to negative as xx crosses π2\frac{\pi}{2}).
  • As a result, tan(x)\tan(x) \to -\infty.

Conclusion:

As xπ2+x \to \frac{\pi}{2}^+, tan(x)\tan(x) \to -\infty.

Would you like more details on the tangent function's asymptotic behavior or related concepts?

Here are some related questions to explore:

  1. What happens to tan(x)\tan(x) as xπ2x \to \frac{\pi}{2}^-?
  2. What is the period of the tangent function?
  3. Why does tan(x)\tan(x) have vertical asymptotes at x=π2+nπx = \frac{\pi}{2} + n\pi?
  4. How is the tangent function related to the unit circle?
  5. What are the key differences between tan(x)\tan(x) and sin(x)\sin(x) or cos(x)\cos(x)?

Tip: Remember that the tangent function is undefined at points where cos(x)=0\cos(x) = 0, leading

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Behavior of Trigonometric Functions
Limits

Formulas

tan(x) = sin(x) / cos(x)

Theorems

Properties of Trigonometric Functions
Vertical Asymptotes in the Tangent Function

Suitable Grade Level

Grades 10-12