Math Problem Statement

Evaluate lim x approaches infinity arctan(x)

Solution

The limit of arctan(x)\arctan(x) as xx approaches infinity can be evaluated as follows:

limxarctan(x)\lim_{x \to \infty} \arctan(x)

The function arctan(x)\arctan(x), also known as the inverse tangent function, has horizontal asymptotes as xx approaches infinity and negative infinity. The asymptote as xx \to \infty is π2\frac{\pi}{2}, since:

  • As xx \to \infty, arctan(x)\arctan(x) approaches but never exceeds π2\frac{\pi}{2}.
  • Similarly, as xx \to -\infty, arctan(x)\arctan(x) approaches π2-\frac{\pi}{2}.

Thus, we have:

limxarctan(x)=π2\lim_{x \to \infty} \arctan(x) = \frac{\pi}{2}

Would you like further details or explanations on this topic?

Here are 5 related questions you might explore:

  1. What is the limit of arctan(x)\arctan(x) as xx \to -\infty?
  2. How does the behavior of the arctangent function compare to other inverse trigonometric functions?
  3. What are the applications of the arctangent function in real-world problems?
  4. How do we derive the asymptotic behavior of arctan(x)\arctan(x) as xx \to \infty?
  5. What is the Taylor series expansion of arctan(x)\arctan(x) and how does it help in evaluating limits?

Tip: When dealing with limits of inverse trigonometric functions, remember their asymptotic behavior and corresponding horizontal asymptotes.

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Inverse Trigonometric Functions

Formulas

lim_{x \to \infty} \arctan(x) = \frac{\pi}{2}

Theorems

Asymptotic behavior of inverse trigonometric functions

Suitable Grade Level

Grades 11-12 (Advanced High School) or Early College