Math Problem Statement

A quadruple (a, b, c, d) of distinct integers is said to be balanced if a + c = b + d . Let S be any set of quadruples (a, b, c, d) where 1 ≤ a < b < d < c ≤ 20 and where the cardinality of S is 4411. Find the least number of balanced quadruples in S

Solution

To solve this problem, we need to find the minimum number of balanced quadruples in a set SS of quadruples (a,b,c,d)(a, b, c, d) where 1a<b<d<c201 \leq a < b < d < c \leq 20 and the cardinality of SS is 4411.

Step 1: Count the total number of quadruples

Given the conditions 1a<b<d<c201 \leq a < b < d < c \leq 20, we need to count the number of valid quadruples.

We can choose four distinct numbers from the set {1,2,,20}\{1, 2, \dots, 20\} and assign them to a,b,c,da, b, c, d in such a way that a<b<d<ca < b < d < c. The number of ways to choose 4 distinct numbers from 20 is given by:

(204)=20×19×18×174×3×2×1=4845\binom{20}{4} = \frac{20 \times 19 \times 18 \times 17}{4 \times 3 \times 2 \times 1} = 4845

For each choice of four numbers, there is exactly one way to assign them to a,b,d,ca, b, d, c such that a<b<d<ca < b < d < c. Therefore, the total number of valid quadruples is 4845.

Step 2: Establish balanced quadruples

A quadruple (a,b,c,d)(a, b, c, d) is balanced if a+c=b+da + c = b + d. To find the least number of balanced quadruples, we need to analyze the structure of the problem.

Step 3: Maximize non-balanced quadruples

The problem asks for the minimum number of balanced quadruples. Since S=4411|S| = 4411, we need to minimize the number of balanced quadruples in this set.

The total number of non-balanced quadruples can be at most 48454411=4344845 - 4411 = 434. So the minimum number of balanced quadruples is:

4845434=44114845 - 434 = 4411

Therefore, to maximize non-balanced quadruples and minimize balanced ones, there must be at least:

4411434=39774411 - 434 = 3977

Thus, the least number of balanced quadruples in SS is 3977.

Final Answer

The minimum number of balanced quadruples in the set SS is:

3977\boxed{3977}

Would you like a deeper explanation on any step, or have more questions?

Here are 5 relative questions you might find interesting:

  1. How would the answer change if the quadruples were chosen from {1,2,,30}\{1, 2, \dots, 30\}?
  2. How do we compute combinations when the constraints on elements differ, like abdca \leq b \leq d \leq c?
  3. What properties do balanced quadruples share, and how can these be used in combinatorial problems?
  4. How do we calculate the probability of randomly selecting a balanced quadruple from the set SS?
  5. Can this method be generalized to other types of quadruples, such as those involving different arithmetic conditions?

Tip: Understanding how to count distinct combinations in problems like these can be greatly enhanced by practicing with smaller sets first, where you can manually verify all possible cases.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Balanced Quadruples
Set Theory

Formulas

Number of ways to choose 4 distinct integers from a set of size n: C(n, 4) = n! / [4!(n-4)!]
Balanced quadruple condition: a + c = b + d

Theorems

Binomial Theorem
Combinatorial Counting

Suitable Grade Level

Grades 11-12 / Early University