Math Problem Statement
How many solutions satisfy 𝑎 + 𝑏 + 𝑐 + 𝑑 ≤ 10 𝑎, 𝑏, 𝑐, 𝑑 ≥ 1
Solution
To solve the problem of finding the number of solutions that satisfy:
we'll transform the inequality and then apply the combinatorial "stars and bars" method.
Step 1: Substitute Variables
Since each variable and must be at least 1, we can let: where and .
Now the inequality becomes:
Simplifying, we get:
Step 2: Convert to an Equality with a New Variable
Let , where . Then, the equation becomes:
Now, we need to find the number of non-negative integer solutions to this equation, which is a classic combinatorial problem.
Step 3: Apply the Stars and Bars Theorem
The number of solutions to the equation in non-negative integers is given by: where and (since we have and ).
Thus, the number of solutions is:
Step 4: Calculate
Conclusion
The number of solutions that satisfy with is:
Would you like more details on any part of this solution?
Here are five related questions that expand on this concept:
- How would the solution change if the inequality were ?
- How does the "stars and bars" method generalize to more variables?
- What would happen if we imposed a stricter upper bound on each variable individually?
- How can we apply similar methods to find integer solutions within a range for each variable?
- How would the solution change if we allowed one of the variables to be zero?
Tip: The stars and bars method is a powerful technique for counting integer solutions to equations, especially useful when dealing with combinatorial inequalities.
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Inequalities
Stars and Bars Method
Formulas
Substitution for non-negative variables: x' = x - 1
Stars and Bars formula: C(n + k - 1, k - 1)
Theorems
Stars and Bars Theorem
Suitable Grade Level
Grades 9-12
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