https://file.aiquickdraw.com/mathbot/file/1726449789073o93vc0zs.jpg

To determine the stress on the beam, we can use the formula for axial stress:

\[
\sigma = \frac{F}{A}
\]

Where:
- \( \sigma \) is the stress in pascals (Pa),
- \( F \) is the axial force (load) in newtons (N),
- \( A \) is the cross-sectional area in square meters (m²).

### Step 1: Convert units
- The axial load is given as 78 kN. Since \(1 \text{kN} = 1000 \text{N}\), the load becomes:
  \[
  F = 78 \times 1000 = 78000 \text{ N}
  \]
  
- The cross-sectional dimensions of the beam are 350 mm by 100 mm. We need to convert this to meters:
  \[
  350 \text{ mm} = 0.350 \text{ m}, \quad 100 \text{ mm} = 0.100 \text{ m}
  \]

### Step 2: Calculate the cross-sectional area
The cross-sectional area \(A\) is the product of the width and height of the beam:
\[
A = 0.350 \times 0.100 = 0.035 \text{ m}^2
\]

### Step 3: Calculate the stress
Now, we can calculate the stress:
\[
\sigma = \frac{78000}{0.035} = 2,228,571.43 \text{ Pa} \quad \text{or} \quad 2.23 \text{ MPa}
\]

Thus, the stress on the beam is approximately **2.23 MPa**.

Would you like more details or have any questions?

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Here are 5 related questions for further understanding:
1. How does the beam length affect stress calculations?
2. What are the consequences of exceeding the material's yield stress?
3. How can we reduce stress in structural beams?
4. What are some common materials used for beams in structural engineering?
5. How does the shape of a beam's cross-section affect its load-bearing capacity?

**Tip:** Always ensure units are consistent when calculating stress to avoid errors.

Consider a 2-m beam with an axial load of 78 kN. Determine the stress if the beam has cross-sectional dimensions of 350 mm by 100 mm.

Learn how to calculate the axial stress on a 2-meter beam with an axial load of 78 kN and cross-sectional dimensions of 350 mm by 100 mm. This problem involves unit conversion and basic mechanical engineering principles. Suitable for undergraduate engineering students.

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