The sequence provided is an arithmetic sequence, where the difference between consecutive terms is constant. You are given the terms:

$\_, 10, \_, 28, \dots$

Let the common difference be $d$. Using this, we can set up the following relationships based on the definition of an arithmetic sequence:

• The second term is 10: $a + d = 10$

• The fourth term is 28: $a + 3d = 28$

Now, subtract the first equation from the second: $(a + 3d) - (a + d) = 28 - 10$ $2d = 18$ $d = 9$

Now, substitute $d = 9$ back into the first equation to find $a$: $a + 9 = 10$ $a = 1$

So the first term is 1, and the common difference is 9. Using this, we can now find the third term: $1 + 2(9) = 1 + 18 = 19$

Thus, the sequence is:

$1, 10, 19, 28, \dots$

The two missing terms are 1 and 19.

Would you like more details or have any questions? Here are five related questions you could explore:

1. How do you find the sum of the first $n$ terms of an arithmetic sequence?
2. What is the formula for the general term of an arithmetic sequence?
3. Can you explain the difference between arithmetic and geometric sequences?
4. How would the sequence change if the common difference were negative?
5. How can arithmetic sequences be applied in real-world problems?

Tip: Always double-check the common difference when working with arithmetic sequences to avoid mistakes in identifying missing terms.