The problem asks to find two missing terms in an arithmetic sequence where we are given part of the sequence: $\_ , 10, \_ , 28$.

Step-by-step solution:

1. In an arithmetic sequence, the difference between consecutive terms is constant. Let's call this common difference $d$.

2. The known terms are $10$ and $28$. So, the difference between these two terms is: $28 - 10 = 18$ Since there is one missing term between them, the difference between consecutive terms (the common difference $d$) will be half of 18: $d = \frac{18}{2} = 9$

3. Now, starting from 10, we add the common difference $d$ to find the next term: $10 + 9 = 19$ So, the missing term between 10 and 28 is $19$.

4. To find the term before 10, subtract the common difference from 10: $10 - 9 = 1$ So, the first missing term is $1$.

Conclusion:

The complete arithmetic sequence is: $1, 10, 19, 28$.

Would you like further details or have any other questions?

Here are 5 related questions you might find helpful:

1. How do you find the common difference in any arithmetic sequence?
2. How can you find the $n$-th term of an arithmetic sequence?
3. What is the formula for the sum of an arithmetic sequence?
4. How do arithmetic sequences differ from geometric sequences?
5. Can an arithmetic sequence have negative terms or a negative common difference?

Tip: When dealing with arithmetic sequences, always check the consistency of the common difference by verifying it between all consecutive terms!