Math Problem Statement

Question 9: La somme S = 100 + 101 + 102 + ... + 140 vaut ? Question 10: (Un)n≥0 est la suite géométrique telle que U20 = 45 et U23 = 5625. La somme S = U18 + U19 + ... + U28 vaut environ ?

Solution

Let's analyze the questions from the image step by step and solve them.


Question 9

The sum S=100+101+102++140S = 100 + 101 + 102 + \dots + 140.

This is an arithmetic series with:

  • First term a=100a = 100,
  • Last term l=140l = 140,
  • Number of terms nn.

We use the formula for the sum of an arithmetic sequence: S=n2×(a+l)S = \frac{n}{2} \times (a + l)

Step 1: Find the number of terms

The number of terms in an arithmetic sequence is: n=lad+1n = \frac{l - a}{d} + 1 where dd is the common difference (here d=1d = 1).

n=1401001+1=41n = \frac{140 - 100}{1} + 1 = 41

Step 2: Calculate the sum

S=412×(100+140)=20.5×240=4920S = \frac{41}{2} \times (100 + 140) = 20.5 \times 240 = 4920

So, the correct answer is: a) 4920\boxed{a) \ 4920}


Question 10

The sequence (Un)n0(U_n)_{n \geq 0} is a geometric progression with:

  • U20=45U_{20} = 45,
  • U23=5625U_{23} = 5625.

We are tasked to find the sum: S=U18+U19++U28.S = U_{18} + U_{19} + \dots + U_{28}.

Step 1: Determine the common ratio (rr)

In a geometric sequence, each term is multiplied by the common ratio rr. Using the formula for the nn-th term: U23=U20r2320=U20r3U_{23} = U_{20} \cdot r^{23-20} = U_{20} \cdot r^3 5625=45r35625 = 45 \cdot r^3 r3=562545=125r=1253=5r^3 = \frac{5625}{45} = 125 \quad \Rightarrow \quad r = \sqrt[3]{125} = 5

Step 2: Express U18U_{18} and the terms

From U20=45U_{20} = 45 and r=5r = 5, we can move backward to find U18U_{18}: U20=U18r2U18=U20r2=4552=4525=1.8U_{20} = U_{18} \cdot r^2 \quad \Rightarrow \quad U_{18} = \frac{U_{20}}{r^2} = \frac{45}{5^2} = \frac{45}{25} = 1.8

Step 3: Find the sum of terms

The sum of a finite geometric series is given by: S=U181rn1rS = U_{18} \cdot \frac{1 - r^{n}}{1 - r} where nn is the number of terms. From U18U_{18} to U28U_{28}, there are: n=2818+1=11 terms.n = 28 - 18 + 1 = 11 \ \text{terms.}

Substitute: S=1.8151115S = 1.8 \cdot \frac{1 - 5^{11}}{1 - 5} S=1.81488281254S = 1.8 \cdot \frac{1 - 48828125}{-4} S=1.8488281244S = 1.8 \cdot \frac{-48828124}{-4} S=1.812207031=21972655.8S = 1.8 \cdot 12207031 = 21972655.8

Approximating, the correct answer is: c) 21972656\boxed{c) \ 21 \, 972 \, 656}


Final Answers:

  • Question 9: a 4920\boxed{a \ 4920},
  • Question 10: c 21972656\boxed{c \ 21 \, 972 \, 656}.

Would you like a more detailed explanation or further breakdown?

Related Questions:

  1. What is the formula for the sum of an arithmetic sequence?
  2. How do you determine the common ratio of a geometric sequence?
  3. What are the conditions for using the geometric series sum formula?
  4. Can you derive the sum formula for an arithmetic series?
  5. How does changing the number of terms in the sequence affect the sum?

Tip:

Always double-check calculations in geometric sequences, especially powers of the common ratio, as they grow very quickly!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Arithmetic sequences
Geometric sequences
Summation of series

Formulas

Sum of arithmetic series: S = (n/2) × (a + l)
Sum of geometric series: S = a × (1 - r^n) / (1 - r)

Theorems

Arithmetic sequence summation formula
Geometric sequence summation formula

Suitable Grade Level

Grades 9-12