Math Problem Statement

If Arg(\overline{z}) = Arg(z), then Arg(z) equals π.

Solution

The provided text in Arabic and mathematical symbols translates to:

"If Arg(z̅) = Arg(z), then Arg(z) equals π."

Here:

  • zz is a complex number.
  • z\overline{z} is the conjugate of zz.
  • Arg(z)\text{Arg}(z) represents the principal argument (angle) of zz.

Explanation

For a complex number zz represented as z=x+yiz = x + yi (where xx is the real part and yy is the imaginary part), the conjugate z\overline{z} is xyix - yi.

  1. The argument Arg(z)\text{Arg}(z) gives the angle of zz in the complex plane relative to the positive real axis.

  2. The argument of z\overline{z}, Arg(z)\text{Arg}(\overline{z}), reflects the angle Arg(z)\text{Arg}(z) over the real axis, so: Arg(z)=Arg(z).\text{Arg}(\overline{z}) = -\text{Arg}(z).

  3. The condition Arg(z)=Arg(z)\text{Arg}(\overline{z}) = \text{Arg}(z) implies: Arg(z)=Arg(z).-\text{Arg}(z) = \text{Arg}(z).

  4. Solving for Arg(z)\text{Arg}(z), we find: Arg(z)=0orArg(z)=π.\text{Arg}(z) = 0 \quad \text{or} \quad \text{Arg}(z) = \pi.

  • Since the problem states that Arg(z)\text{Arg}(z) equals π\pi, the argument of zz corresponds to an angle of π\pi radians, meaning zz lies on the negative real axis.

Summary

  • Arg(z)=π\text{Arg}(z) = \pi indicates that zz is a real number with a negative value.

Would you like a graphical explanation or further clarification?


Related Questions:

  1. What is the argument of a complex number, and how is it calculated?
  2. How is the conjugate of a complex number geometrically represented?
  3. Why does Arg(z)=Arg(z)\text{Arg}(\overline{z}) = -\text{Arg}(z) hold true?
  4. What are the principal and general arguments of a complex number?
  5. Can a complex number have an argument equal to π\pi and still have a non-zero imaginary part?

Tip: For any complex number zz on the negative real axis, its argument is always π\pi.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Argument of a Complex Number
Complex Conjugates

Formulas

Arg(\overline{z}) = -Arg(z)
If Arg(\overline{z}) = Arg(z), then Arg(z) = 0 or Arg(z) = π

Theorems

Argument of Complex Conjugate Theorem

Suitable Grade Level

Grades 10-12