The image shows a trapezoid with a height of 5 units and two bases. The length of the top base (EC) is given as 20 units, and the length of the bottom base (AB) is given as 20 units. The height of the trapezoid from point A to point E is 10 units.

The formula for the area $A$ of a trapezoid is:

$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Where:

• $b_1$ and $b_2$ are the lengths of the two parallel sides (the bases), and
• $h$ is the height.

Here, we have:

• $b_1 = 20$ units (top base),
• $b_2 = 20$ units (bottom base),
• $h = 5$ units (height).

Substitute the values into the area formula:

$A = \frac{1}{2} \times (20 + 20) \times 5 = \frac{1}{2} \times 40 \times 5 = 100$

So, the area of the trapezoid is 100 square units.

Would you like a more detailed explanation or have any further questions? Here are some related questions:

1. How do we handle irregular trapezoids with different base lengths?
2. Can this formula be used for triangles and other polygons?
3. How do we find the area of a parallelogram?
4. What is the significance of the height in calculating the area of polygons?
5. How does changing the height affect the area of the trapezoid?

Tip: When calculating the area of trapezoids, always ensure to measure the height perpendicular to the parallel sides!