To solve the problem, we need to calculate the area of trapezoid $ABCD$.

Formula for the Area of a Trapezoid:

$\text{Area} = \frac{1}{2} \cdot (\text{Base}_1 + \text{Base}_2) \cdot \text{Height}$

Given Dimensions:

• Base $AB = 8$ units
• Base $CD = 20$ units
• Height = $6$ units (the perpendicular distance between the two bases)

Substituting into the formula:

$\text{Area} = \frac{1}{2} \cdot (8 + 20) \cdot 6$

1. Add the two bases: $8 + 20 = 28$

2. Multiply by the height: $28 \cdot 6 = 168$

3. Divide by 2: $\text{Area} = \frac{168}{2} = 84$

Area = $84 \, \text{square units}$.

However, none of the options matches exactly. Can you verify the provided values? It seems there might be a mismatch.

Would you like me to recheck any specific details or explain further? Here are related questions you might want to explore:

1. What happens if the height or one base is misinterpreted?
2. How is the height of a trapezoid determined geometrically?
3. Why do we average the bases in the trapezoid formula?
4. How does this formula compare with the area formulas for other quadrilaterals?
5. Could rounding errors impact a similar calculation?

Tip: Double-check measurements and given dimensions in geometry problems to ensure clarity!