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It looks like you're working with a piecewise function. The problem shown is:

\[
f(x) =
\begin{cases} 
\frac{2x^2 - 5x - 3}{x - 3}, & \text{if } x \neq 3 \\
6, & \text{if } x = 3
\end{cases}
\]

The goal might involve finding the limit of \( f(x) \) as \( x \to 3 \), ensuring that the function is continuous, or analyzing the function behavior at \( x = 3 \).

Would you like me to analyze this further or perform any specific operation, such as finding the limit or determining the continuity at \( x = 3 \)?

Here are 5 possible questions based on this function:
1. What is the limit of \( f(x) \) as \( x \to 3 \)?
2. Is \( f(x) \) continuous at \( x = 3 \)?
3. How do you simplify the expression \( \frac{2x^2 - 5x - 3}{x - 3} \)?
4. What is the value of \( f(x) \) at \( x = 3 \), and how does it relate to continuity?
5. How would the function change if \( a = 3 \) were modified?

**Tip**: Always check if a function is continuous by ensuring that the limit as \( x \) approaches the point matches the function's value at that point.

f(x) = { (2x^2 - 5x - 3) / (x - 3), if x ≠ 3; 6, if x = 3. What can be deduced about the behavior of the function at x = 3?

Explore how to determine the continuity and limits of the function f(x) at x = 3, where the function is piecewise defined. This example includes key concepts of limits, algebra, and continuity, making it suitable for students in Grades 10-12.

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