Math Problem Statement
Solution
From the graph provided, let's analyze the points and limits to answer the questions.
Step-by-Step Analysis:
1. :
- From the graph, at , the corresponding -value (or ) is clearly marked at 5.
- Answer:
2. :
- We need to examine the behavior of as approaches 5 from both sides (left and right).
- From the left (), approaches 3.
- From the right (), also approaches 3.
- Since both limits agree, the two-sided limit exists and equals 3.
- Answer:
3. :
- This asks for the right-hand limit as approaches 1.
- Approaching from the right (), approaches 1 (since the value approaches the point at ).
- Answer:
4. :
- At , there is a jump discontinuity in the graph.
- The limit from the left () approaches 2, while the limit from the right () approaches 3.
- Since the left and right limits do not match, the limit does not exist.
- Answer:
Summary of Answers:
Would you like more details on any of these? Here are some related questions you might find interesting:
- What is the difference between one-sided and two-sided limits?
- How do you determine continuity of a function using limits?
- Can a function be differentiable if it has a jump discontinuity?
- How do you calculate the limit at a point of removable discontinuity?
- Why are limits important in calculus?
Tip: When analyzing limits, always check the behavior from both sides of the point. If the left-hand and right-hand limits are unequal, the overall limit does not exist!
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Math Problem Analysis
Mathematical Concepts
Limits
Continuity
Discontinuity
Piecewise Functions
Formulas
Limit from the left: lim(x -> c^-) f(x)
Limit from the right: lim(x -> c^+) f(x)
Theorems
Definition of Continuity: A function f is continuous at x = c if lim(x -> c) f(x) = f(c)
Existence of Limit: A limit exists at x = c if the left-hand limit and right-hand limit are equal
Suitable Grade Level
Grade 11-12
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