Math Problem Statement

Aşağıdakilerden hangisi (hangileri) her zaman doğrudur? I) {(x, y, z) | x + y ≤ 0} kümesi R³ uzayının bir altuzayıdır. II) T : R² → R², T(x, y) = (x + 2, y) dönüşümü bir lineer dönüşümdür. III) T : R³ → R³, T(x, y, z) = (0, x + z, y) lineer dönüşümü altında y = 0 düzleminin görüntüsü y-eksenidir.

Solution

The problem presents three mathematical statements and asks which of them are always true. Here's an analysis of each statement:


Statement I:

The set {(x,y,z)x+y0}\{(x, y, z) \mid x + y \leq 0\} is a subspace of R3\mathbb{R}^3.
Analysis:
For a set to be a subspace of R3\mathbb{R}^3, it must satisfy the following conditions:

  1. It must include the zero vector (0,0,0)(0, 0, 0),
  2. It must be closed under vector addition,
  3. It must be closed under scalar multiplication.

Let us test:

  • The zero vector (0,0,0)(0, 0, 0) satisfies x+y=0+0=00x + y = 0 + 0 = 0 \leq 0, so it is included.
  • For any (x1,y1,z1)(x_1, y_1, z_1) and (x2,y2,z2)(x_2, y_2, z_2) in the set, x1+y10x_1 + y_1 \leq 0 and x2+y20x_2 + y_2 \leq 0, but their sum (x1+x2)+(y1+y2)(x_1 + x_2) + (y_1 + y_2) could violate this inequality.
    For example: (x1,y1,z1)=(1,1,0)(x_1, y_1, z_1) = (-1, 1, 0) and (x2,y2,z2)=(1,1,0)(x_2, y_2, z_2) = (-1, 1, 0). While both satisfy x+y0x + y \leq 0, their sum is (2,2,0)(-2, 2, 0), where 2+2=0≰0-2 + 2 = 0 \not\leq 0.

Thus, it is not a subspace of R3\mathbb{R}^3.


Statement II:

The transformation T:R2R2T: \mathbb{R}^2 \to \mathbb{R}^2 given by T(x,y)=(x+2,y)T(x, y) = (x + 2, y) is a linear transformation.
Analysis:
To check if a function T(x,y)T(x, y) is linear:

  1. It must satisfy T(u+v)=T(u)+T(v)T(u + v) = T(u) + T(v),
  2. It must satisfy T(cu)=cT(u)T(cu) = cT(u), where u,vR2u, v \in \mathbb{R}^2 and cRc \in \mathbb{R}.

Here,
T(x,y)=(x+2,y)T(x, y) = (x + 2, y). Test the zero vector:

  • T(0,0)=(0+2,0)=(2,0)(0,0)T(0, 0) = (0 + 2, 0) = (2, 0) \neq (0, 0).

Since T(0)0T(0) \neq 0, the function is not linear.


Statement III:

The transformation T:R3R3T: \mathbb{R}^3 \to \mathbb{R}^3, given by T(x,y,z)=(0,x+z,y)T(x, y, z) = (0, x + z, y), maps the plane y=0y = 0 to the yy-axis.
Analysis:
For any point (x,0,z)(x, 0, z) on the plane y=0y = 0,
T(x,0,z)=(0,x+z,0)T(x, 0, z) = (0, x + z, 0).

The image under TT always lies on the yy-axis because the second coordinate (x+z)(x + z) corresponds to the yy-axis, while the first and third coordinates are always 00.
Thus, this statement is true.


Answer:

Only Statement III is always true.
The correct choice is C) III.


Do you want further explanation, or do you have any additional questions?
Here are some related questions to explore:

  1. What conditions must be satisfied for a set to be a subspace of Rn\mathbb{R}^n?
  2. What are the properties of linear transformations?
  3. How can you determine the image of a plane under a linear transformation?
  4. How can the zero vector test verify a subspace or linear transformation?
  5. Can you provide another example of a transformation that isn't linear?

Tip: Always check the zero vector and operations (addition/scalar multiplication) to verify linearity and subspaces.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Subspaces
Linear Transformations

Formulas

Subspace conditions: closure under addition and scalar multiplication, inclusion of the zero vector
Linearity conditions: T(u + v) = T(u) + T(v), T(cu) = cT(u)

Theorems

Definition of a subspace in vector spaces
Properties of linear transformations

Suitable Grade Level

University level (Linear Algebra)