https://file.aiquickdraw.com/mathbot/file/17293991644951frxmkar.jpg

Let's break down the problem and solve it step by step.

### Given:
- Eugene, Jayson, and Cheko saved a total of $7.80.
- Jayson saved 4 times as much as Eugene.
- Cheko saved 2 times as much as Jayson.

### Define variables:
- Let $ E $ represent the amount saved by Eugene.
- Since Jayson saved 4 times as much as Eugene, Jayson saved $ 4E $.
- Since Cheko saved 2 times as much as Jayson, Cheko saved $ 2 \times 4E = 8E $.

### Total saved:
The total amount saved by all three is $7.80:
\[
E + 4E + 8E = 7.80
\]

Simplify the equation:
\[
13E = 7.80
\]

Now, solve for $ E $:
\[
E = \frac{7.80}{13} = 0.60
\]

So, Eugene saved $0.60.

### Amount saved by Cheko:
Cheko saved $ 8E $, so:
\[
8 \times 0.60 = 4.80
\]

Thus, **Cheko saved $4.80**.

Let me know if you want more details or have any questions!

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Here are five related questions for further practice:
1. If Jayson saved 4 times as much as Eugene and Cheko saved $3 more than Jayson, how much did Cheko save if the total was $15?
2. If Eugene saved $1.20, how much did Cheko save under the same conditions?
3. What would be the total amount saved if Jayson only saved 3 times as much as Eugene?
4. If Cheko saved 1.5 times as much as Jayson instead of 2, how much would Cheko save?
5. If the total savings were increased to $10, how would that affect each person's savings?

**Tip:** Always define variables clearly when working with word problems to create easy-to-solve equations.

Eugene, Jayson, and Cheko saved their allowance regularly. Jayson saved 4 times as much as Eugene's money. Cheko saved 2 times as much as Jayson's money. They saved $7.80 altogether. How much did Cheko save?

Learn how to solve an allowance savings problem where Jayson saved 4 times as much as Eugene, and Cheko saved 2 times as much as Jayson. The total savings is $7.80. This solution includes key algebraic concepts and steps to determine how much Cheko saved. Suitable for students in Grades 6-8.

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