Math Problem Statement

Based on the query submitted by the user and the corresponding solution, generate the following information in JSON format.

Solution

Let's break down and solve the questions from the image:

Questions 1–3:

**Given dataLet's break down and solve the questions from the image:

Questions 1–3:

**Given **

  • x1=22x_1 = 22, x2=18x_2 = 18, x3=25x_3 = 25, x4=20x_4 = 20, x5=12x_5 = 12, x6=17x_6 = 17, x7=25x_7 = 25, x8=26x_8 = 26, x9=16x_9 = 16, x10=20x_{10} = 20
  1. Evaluate i=110xi\sum_{i=1}^{10} x_i
    This is the sum of the values from x1x_1 to x10x_{10}.

    i=110xi=22+18+25+20+12+17+25+26+16+20\sum_{i=1}^{10} x_i = 22 + 18 + 25 + 20 + 12 + 17 + 25 + 26 + 16 + 20 Calculating the sum gives:
    i=110xi=201\sum_{i=1}^{10} x_i = 201 Answer: D. 201

  2. Evaluate i=46xi2\sum_{i=4}^{6} x_i^2
    This is the sum of the squares of x4x_4, x5x_5, and x6x_6.

    x42=202=400,x52=122=144,x62=172=289x_4^2 = 20^2 = 400,\quad x_5^2 = 12^2 = 144,\quad x_6^2 = 17^2 = 289 i=46xi2=400+144+289=833\sum_{i=4}^{6} x_i^2 = 400 + 144 + 289 = 833 Answer: B. 833

  3. Evaluate i=374xi\sum_{i=3}^{7} 4x_i
    This is the sum of four times xix_i for i=3i = 3 to i=7i = 7.

    4x3=4×25=100,4x4=4×20=80,4x5=4×12=48,4x6=4×17=68,4x7=4×25=1004x_3 = 4 \times 25 = 100,\quad 4x_4 = 4 \times 20 = 80,\quad 4x_5 = 4 \times 12 = 48,\quad 4x_6 = 4 \times 17 = 68,\quad 4x_7 = 4 \times 25 = 100 i=374xi=100+80+48+68+100=396\sum_{i=3}^{7} 4x_i = 100 + 80 + 48 + 68 + 100 = 396 Answer: A. 396

Questions 4–6:

Given:

  • a1=23a_1 = 23 and i=112ai=947\sum_{i=1}^{12} a_i = 947
  1. Find i=11210ai\sum_{i=1}^{12} 10a_i
    This is 10 times the sum of a1a_1 to a12a_{12}.

    i=11210ai=10×i=112ai=10×947=9470\sum_{i=1}^{12} 10a_i = 10 \times \sum_{i=1}^{12} a_i = 10 \times 947 = 9470 Answer: B. 9470

  2. Find i=112(5ai24)\sum_{i=1}^{12} (5a_i - 24)
    This can be split into two sums:
    i=112(5ai24)=5i=112ai12×24\sum_{i=1}^{12} (5a_i - 24) = 5\sum_{i=1}^{12} a_i - 12 \times 24 =5×947288=4735288=4447= 5 \times 947 - 288 = 4735 - 288 = 4447 Answer: B. 4447

  3. Find i=212(2ai+5)\sum_{i=2}^{12} (2a_i + 5)
    This can be split into two sums:
    i=212(2ai+5)=2i=212ai+11×5\sum_{i=2}^{12} (2a_i + 5) = 2 \sum_{i=2}^{12} a_i + 11 \times 5 Since i=212ai=i=112aia1=94723=924\sum_{i=2}^{12} a_i = \sum_{i=1}^{12} a_i - a_1 = 947 - 23 = 924: 2×924+55=1848+55=19032 \times 924 + 55 = 1848 + 55 = 1903 Answer: D. 1903

If you would like to go further with the remaining problems or any additional details, let me know!

Expanding Questions:

  1. What is the formula for calculating the sum of squares i=1nxi2\sum_{i=1}^{n} x_i^2?
  2. How does the inclusion of constants (like 5 in question 5) affect summation?
  3. How is the arithmetic series sum calculated when there is a linear transformation inside the sum (e.g., 2ai+52a_i + 5)?
  4. What patterns or simplifications can be used when working with sums involving constants and variables?
  5. How would you calculate a sum involving multiple nested sums?

Tip:

When evaluating complex summations, try breaking them into simpler, more manageable parts—this can make calculations faster and more accurate!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Summation
Arithmetic Operations

Formulas

Sum of an arithmetic series: S = n/2(2a + (n-1)d)
Sum of squares: sum(x_i^2) for i in range
Linear transformation in summation

Theorems

Arithmetic series theorem

Suitable Grade Level

High School